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Part A. Synthesis of Sodium Carbonate 1. Mass of large test tube (empty) 31.254 g 2. Mass of large test tube with NaHCO, 33.811 g 3. Mass of NaHCO, 84 g mol 32.883 g 4. Mass of test tube and Na,CO, 106 g mol 5. Mass of Na,CO, (actual yield of Na,CO,) Theoretical yield of product (Na,CO,) calculated from your mass of starting material (NaHCO,). See Example 1. Show the setup for your calculation below. Number of moles of NaHCO3 = 2.557g /84g m 0.0304 moles Moles of Na2CO3 1.629g/106 gmol 0.01533 mole 2NaHCo3 --> Na2Co3 +H2O + CO2 I Mole 0.0152 mol Theoretical yield of Na CO, !!

Part A. Synthesis of Sodium Carbonate 1. Mass of large test tube (empty) 31.254 g 2. Mass of large test tube with NaHCO, 33.811 g 3. Mass of NaHCO, 84 g mol 32.883 g 4. Mass of test tube and Na,CO, 106 g mol 5. Mass of Na,CO, (actual yield of Na,CO,) Theoretical yield of product (Na,CO,) calculated from your mass of starting material (NaHCO,). See Example 1. Show the setup for your calculation below. Number of moles of NaHCO3 = 2.557g /84g m 0.0304 moles Moles of Na2CO3 1.629g/106 gmol 0.01533 mole 2NaHCo3 --> Na2Co3 +H2O + CO2 I Mole 0.0152 mol Theoretical yield of Na CO, !!

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Based on my percent yield, would it be successful? Use the source on the second photo.
Part A. Synthesis of Sodium Carbonate 1. Mass of large test tube (empty) 31.254 g 2. Mass of large test tube with NaHCO, 33.811 g 3. Mass of NaHCO, 84 g mol 4. Mass of test tube and Na,CO, 32.883 g 106 g mol 5. Mass of Na, CÓ, (actual yield of Na,CO,) Theoretical yield of product (Na,CO.) calculated from your mass of starting material (NaHCO,). See Example 1. Show the Number of moles of NalHCO3 2.557g/84em 0.0304 moles Moles of Na2CO3 = 1.629g/106 gmol 0.01533 mole setup for your calculation below 2NaHCo3 ->Na2Co3 + H2O + CO2 I Mole 0.0152 mol Theoretical yield of Na CO, 99.346 9% Percent yield of Na CO,
Transcribed Image Text:Part A. Synthesis of Sodium Carbonate 1. Mass of large test tube (empty) 31.254 g 2. Mass of large test tube with NaHCO, 33.811 g 3. Mass of NaHCO, 84 g mol 4. Mass of test tube and Na,CO, 32.883 g 106 g mol 5. Mass of Na, CÓ, (actual yield of Na,CO,) Theoretical yield of product (Na,CO.) calculated from your mass of starting material (NaHCO,). See Example 1. Show the Number of moles of NalHCO3 2.557g/84em 0.0304 moles Moles of Na2CO3 = 1.629g/106 gmol 0.01533 mole setup for your calculation below 2NaHCo3 ->Na2Co3 + H2O + CO2 I Mole 0.0152 mol Theoretical yield of Na CO, 99.346 9% Percent yield of Na CO,
Based on your percent yield, do you consider the reaction to produce Na,CO, from NaHCO, successful? If your yield is greater than 100%, you must give an explanation (see page 156). REPORT SHEET 163
Transcribed Image Text:Based on your percent yield, do you consider the reaction to produce Na,CO, from NaHCO, successful? If your yield is greater than 100%, you must give an explanation (see page 156). REPORT SHEET 163
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