A 100 mg sample of a compound containing C, H, and O is analyzed. All the carbon is converted to CO_2 with mass 176 mg. All hydrogen is converted to H_2O (water) with mass 36 mg. Goal: determine empirical formula, molecular formula if there are 8 carbon atoms per molecule, and molar mass.

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A 100 mg sample of a compound containing C, H, and O is analyzed. All the carbon is converted to CO_2 with mass 176 mg. All hydrogen is converted to H_2O (water) with mass 36 mg. Goal: determine empirical formula, molecular formula if there are 8 carbon atoms per molecule, and molar mass. My work is attached but I am not understanding the last two parts. Thank you.
8.
100
.mg .sample... Cx. Hy Oz
CO₂
w/ mass.
.mg
.wl. mass
36 mg.
need empircal formula, molecular formula, molan mass
CO₂ = (2.01 + 2 (16.00) = 44,01
All C
All H
mg
36
converted to
converted
0.176 A.
44.01.4.
.mol
X
туд х
6..036. g.
18.02.
.mal
H₂0 = 2(1.008) + 16.00
4.00 mot. C.
.
2.00 myt H
C: 48.04.
2.016
.
10-3 g
.
=
to
1 mg.
10-3
H₂0.
.1.mg
.
0.00 3999 .=.4.00
·0.00.199
12.01 g
myt
0.176
1.0089
mo!
23.83 =24
2
0.036
=
g.
18.016
emporal C 24 H₁ H₂4 C₁ →
formala
24
9
mol.
2.00.
५४.०५
176
8. C.atams.
g
2.016
x 10-³ mol.
molecule.
x 10-3 mal
= 18.02 g (4 SF)
g
C. = mass
.co.₂
= 2.016 = 1
2,016
molecular formula
H₂0. (.3 SF).
of C
H = mass of.H.
(3 SF)
molan mass.
(6 (1.008) +12 (12.01) =
160.2 a
mol
Why minus 8
instead of dividing by 8?
Transcribed Image Text:8. 100 .mg .sample... Cx. Hy Oz CO₂ w/ mass. .mg .wl. mass 36 mg. need empircal formula, molecular formula, molan mass CO₂ = (2.01 + 2 (16.00) = 44,01 All C All H mg 36 converted to converted 0.176 A. 44.01.4. .mol X туд х 6..036. g. 18.02. .mal H₂0 = 2(1.008) + 16.00 4.00 mot. C. . 2.00 myt H C: 48.04. 2.016 . 10-3 g . = to 1 mg. 10-3 H₂0. .1.mg . 0.00 3999 .=.4.00 ·0.00.199 12.01 g myt 0.176 1.0089 mo! 23.83 =24 2 0.036 = g. 18.016 emporal C 24 H₁ H₂4 C₁ → formala 24 9 mol. 2.00. ५४.०५ 176 8. C.atams. g 2.016 x 10-³ mol. molecule. x 10-3 mal = 18.02 g (4 SF) g C. = mass .co.₂ = 2.016 = 1 2,016 molecular formula H₂0. (.3 SF). of C H = mass of.H. (3 SF) molan mass. (6 (1.008) +12 (12.01) = 160.2 a mol Why minus 8 instead of dividing by 8?
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