Part AHow many grams of Li,N can be formed from 1.75 moles of Li? Assume an excess of nitrogen.6 Li(s) + N2(g) → 2 Li,N(s)O 15.1 g LigNO 20.3 g LigNO 18.3 g LigN58.3 g LizN61.0 g LigNSubmitRequest Answer< Return to AssignmentProvide Feedback

6 mole of Li forms 3 mole of Li3N 1.75 mole of Li forms 0.583 mole of Li3N

Part A How many grams of LigN can be formed from 1.75 moles of Li? Assume an excess of nitrogen. 6 Li(s) + N2(g) – 2 LigN(5) O 15.1 g LigN O 20.3 g LigN O 18.3g LigN 58.3 g LigN 61.0 g LigN Submit Request Answer

Part A How many grams of LigN can be formed from 1.75 moles of Li? Assume an excess of nitrogen. 6 Li(s) + N2(g) – 2 LigN(5) O 15.1 g LigN O 20.3 g LigN O 18.3g LigN 58.3 g LigN 61.0 g LigN Submit Request Answer

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

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Part A
How many grams of Li,N can be formed from 1.75 moles of Li? Assume an excess of nitrogen.
6 Li(s) + N2(g) → 2 Li,N(s)
O 15.1 g LigN
O 20.3 g LigN
O 18.3 g LigN
58.3 g LizN
61.0 g LigN
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Question Completion Status: P205 Phosphorus Oxygen 1 molecule 2 atoms of P 5 atoms of O of P205 3 molecules of P205 6 atoms of P 15 atoms of O 4 molecules of P205 atoms of P atoms of O (NH4)2SO3 Nitrogen Hydrogen Sulfur Oxygen 1 ionic compound of (NH4)2SO3 atoms of S atoms of O atoms of N atoms of H 2 ionic compounds of (NH4)2S03 atoms of N atoms of H atoms of S atoms of O 5 ionic compounds of (NH4)2SO3 atoms of N atoms of H atoms of S atoms of O QUESTION 2
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