Part A What is the thickness of the film in terms of the light wavelength inside it? Express your answer as a multiple of wavelength to two significant figures. ? d = Submit Request Answer Part B Are the reflections from the film surfaces inverted or not? Reflection from the right surface of the film is inverted while reflection from the left surface of the film is not. Reflections from the both surfaces of the film are inverted. Reflection from the left surface of the film is inverted while reflection from the right surface of the film is not. Reflections from the both surfaces of the film are not inverted.
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- Newton's rings are visible when a planoconvex lens is placed on a flat glass surface. For a particular lens with an index of refraction of n = 1.50 and a glass plate with an index of n = 1.80, the diameter of the third bright ring is 0.740 mm. Part A If water (n = 1.33) now fills the space between the lens and the glass plate, what is the new diameter of this ring? Assume the radius of curvature of the lens is much greater than the wavelength of the light. Express your answer with the appropriate units. d= Value Units ?Please only answer question 9. I included question 8 as well to give the background of the question. Please give a detailed explanation for why the total internal reflection occurs when the incident angle is greater than the critical angle. Please explain each step carefully with good reasoning.A beam of light is emitted 8.0 cm beneath the surface of a liquid and strikes the surface 7.5 cm from the point directly above the source. Part A If total internal reflection occurs, what can you say about the index of refraction of the liquid? Express your answer using two significant figures. ΑΣΦ nliquid > Submit Request Answer Provide Feedback Constant
- Incident white light in air (nair=1) encounters a a piece of plastic as shown in the figure below. The index of refraction for blue light is ng=1.36 and the index of refraction for red light is ng=1.28. After the light passes through the first boundary, the blue light undergoes total internal reflection when it encounters the plastic to air boundary from the inside at exactly the critical angle. The red light gets refracted when it encounters the plastic to air boundary from the inside. a) Draw and label a qualitative ray diagram for the light rays for the whole process. b) Find the incident angle of the white light. (you have to really think about what is incident and what is transmitted) c) Using the result from (b), find the angle the red light exits the plastic (no additional points will be taken off if your fırst result is incorrect). air MacBook ProLight is incident normally on the short face of a 30°-60°-90° prism (Figure 1). A drop of liquid is placed on the hypotenuse of the prism. Figure 1 of 1 30° 90°Light with a frequency of 5.50x1014 Hz travels in a block of glass that has an index of refraction of 1.52. Part A What is the wavelength of the light in vacuum? Express your answer in meters. —| ΑΣΦ λ = Submit Part B Request Answer What is the wavelength of the light in the glass? Express your answer in meters. —| ΑΣΦ λ = ? ? m m
- Unpolarized light is directed on Glan-Air prism at normal incidence as shown on the right sketch. The prisms' are made of calcite with n=1.4864 and n1=1.6584. Determine the minimum and maximum OOA values for apex angle 0 so that s- polarized component of the incoming light is transmitted while p-polarized light is totally reflected. OAA flat piece of glass covers the top of a vertical cylinder that is completely filled with water. If a ray of light traveling in the glass is incident on the interface with the water at an angle of a = 36.0°, the ray refracted into the water makes an angle of 49.0° with the normal to the interface. Part A What is the smallest value of the incident angle for which none of the ray refracts into the water? Express your answer in degrees. VE ΑΣΦIn the figure, a 1.6-m-long vertical pole extends from the bottom of a swimming pool to a point 50.0 cm above the water. Sunlight is incident at angle 0 = 46.0°. What is the length in meters of the shadow of the pole on the level bottom of the pool? The water has an index of refraction of 1.33. Blocked sunrays Number i Units
- I Review A 5.0 cm -thick layer of oil is sandwiched between a 1.7 Cm -thick sheet of glass and a 2.3 cm -thick sheet of polystyrene plastic. Part A How long (in ns) does it take light incident perpendicular to the glass to pass through this 9.0 cm -thick sandwich? Express your answer to two significant figures and include the appropriate units. HA ? t = Value Units Submit Request AnswerYou (height of your eyes above the water, h = 1.80 m) are standing 2.00 m from the edge of a 2.50-m-deep swimming pool (Figure 1). You notice that you can barely see your cell phone, which went missing a few minutes before, on the bottom of the pool. The index of refraction of water at this temperature is 1.333. Part A How far from the side of the pool is your cell phone? Express your answer with the appropriate units. ? d = 1.841 m Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Provide Feedback gure 1 of 1 K2.00 m 2.50 m