9. Does total internal reflection occur for incident angles greater than or less than ee ? 1.C
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Please only answer question 9. I included question 8 as well to give the background of the question. Please give a detailed explanation for why the total internal reflection occurs when the incident angle is greater than the critical angle. Please explain each step carefully with good reasoning.
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- Which of the following statements are true? Choose all that apply. O If light from a star passes through an exoplanet's atmosphere, we can look at the absorption spectra to determine what elements & compounds are in the atmosphere. O For a telescope, decreasing f, will increase the actual size of the image seen by the person looking through the telescope. O In crown glass, the index of refraction for blue light is 1.524 and for green light it is 1.519. Thus in crown glass, blue light is slower than green light. O If unpolarized light is incident on a polarizer, 0% will pass through. O The glasses for farsighted people create virtual images for them to see. O The smaller the diameter of an optic is, the larger the minimum angle it can discern is.Calculate the critical angle for the light traveling from glass (n glass= 1.54) to air (n=1.00). Express your answer in degrees. Normal format with 3 SF. airA ray of light travels through air until it strikes the interface between the air and another medium. The incident ray makes an angle of 0, = 32.0° with the normal, as shown in the figure below. Upon passage into the second medium, the ray is refracted, emerging from the interface at an angle 0, with respect to the normal. Air Second medium (a) Suppose that the second medium is polystyrene. What is the angle of refraction, 8, (in degrees)? (Enter your answer to at least one decimal place.) (b) Suppose that the second medium is sodium chloride. What is the angle of refraction, 8,, in this case (in degrees)? (Enter your answer to at least one decimal place.) (c) Finally, suppose that the second medium is glycerine. What is the angle of refraction, 0,, in this case (in degrees)? (Enter your answer to at least one decimal place.)
- A light ray is incident perpendicular to the left face of the shown prism made of glass (n = 1.6). What is the largest value of the angle p such that the light ray is totally reflected at the far right face if the prism is surrounded by air? Express your answer to the nearest degree.The critical angle for total internal reflection at a liquid-air interface is 45.0°. Part A If a ray of light traveling in the liquid has an angle of incidence at the interface of 34.0 °, what angle does the refracted ray in the air make with the normal? Express your answer in degrees. ΑΠΑΣΦ 0 = Submit Part B Request Answer 0 = ? If a ray of light traveling in air has an angle of incidence at the interface of 34.0 °, what angle does the refracted ray in the liquid make with the normal? Express your answer in degrees. —| ΑΣΦ 2 ? O9
- Diamond is known for being a particularly brilliant stone. The reason behind this is its peculiarly high index of refraction, n = 2.4. A ray of light within a diamond hits the diamond-air (n = 1) interface. Calculate the critical angle for diamond such that the ray be totally internally reflected. Critical angle for diamond-air interface = 0 Once you have determined this, compare the critical angle to the one in the figure below, which is for a glass-air interface? Knowing that glass has a smaller refractive index than diamond, which material will have a larger critical angle. n2=1 n1 =1.5 39° 90° 41.8° 45° 45° Difference between the cirtical angles between the diamond-air and glass-air interface is (report the absolute value of the difference) 0 What is the significance of this comparison with regards to the brilliance of diamond?I need help with problems A,B,C,D and E. I am really struggling with this problem I asked my professor and he won't help me. I was wondering if you can help me solve these problems. Also, Can you label which problem is A,B,C,D and E. Thank youA beam of light is incident from air on the surface of a liquid. If the angle of incidence is 36.2° and the angle of refraction is 25.0°, find the critical angle for the liquid when surrounded by air. Step 1 When light goes from one material into another having a higher index of refraction, the light bends toward the normal line as shown in part (a) of the diagram. 02 air liquid (a) (b) We are given that when = 36.2°, the angle of refraction in the liquid is = 25.0°. Thus, from Snell's law, the index of refraction of the liquid is nliquid = nair sin sin e = (1.00) sin sin 25.0° 0 (0.423)
- Part A A sharp image is located 391 mm behind a 263-mm-focal-length converging lens. Find the object distance. Follow the sign conventions. Express your answer to three significant figures and include the appropriate units. HA do = Value Units Submit Request Answer Provide Feedback Next>Light travels from crown glass into air. (Refer to Table 1 for the indexes of refraction.) The angle of refraction in air is 60.0°. Calculate the angle of incidence in the crown glass.Describe the working principles of fiber optics. How does total internal reflection play a crucial role in transmitting light through optical fibers?