In the figure, a 2.0-m-long vertical pole extends from the bottom of a swimming pool to a point 50.0 cm above the water. Sunlight is incident at angle 0 = 53.0°. What is the length in meters of the shadow of the pole on the level bottom of the pool? The water has an index of refraction of 1.33. Blocked sunrays Number i Units
In the figure, a 2.0-m-long vertical pole extends from the bottom of a swimming pool to a point 50.0 cm above the water. Sunlight is incident at angle 0 = 53.0°. What is the length in meters of the shadow of the pole on the level bottom of the pool? The water has an index of refraction of 1.33. Blocked sunrays Number i Units
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![In the figure, a 2.0-m-long vertical pole extends from the bottom of a swimming pool to a point 50.0 cm above the water. Sunlight is incident at angle \( \theta = 53.0^\circ \). What is the length in meters of the shadow of the pole on the level bottom of the pool? The water has an index of refraction of 1.33.
### Diagram Explanation:
The diagram shows a vertical pole partially submerged in a swimming pool, with the top part extending out above the water surface. Sunlight, represented by red lines, is incident at an angle of \( 53.0^\circ \) to the horizontal. Part of the sunlight is blocked by the pole, casting a shadow on the bottom of the pool. The angle \( \theta \) marks the incident angle of the sunlight. The water’s surface is depicted as a boundary line, and the index of refraction for the water is provided as 1.33.
### Calculation Field:
- **Number**: [Input field for entering the calculated length of the shadow]
- **Units**: [Dropdown menu for selecting units of measurement]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5774cab0-bd8d-4666-9c33-ff33af09f822%2F48f37df9-f0af-4e66-8689-749d6c3dbd13%2Fpgwhqvi_processed.png&w=3840&q=75)
Transcribed Image Text:In the figure, a 2.0-m-long vertical pole extends from the bottom of a swimming pool to a point 50.0 cm above the water. Sunlight is incident at angle \( \theta = 53.0^\circ \). What is the length in meters of the shadow of the pole on the level bottom of the pool? The water has an index of refraction of 1.33.
### Diagram Explanation:
The diagram shows a vertical pole partially submerged in a swimming pool, with the top part extending out above the water surface. Sunlight, represented by red lines, is incident at an angle of \( 53.0^\circ \) to the horizontal. Part of the sunlight is blocked by the pole, casting a shadow on the bottom of the pool. The angle \( \theta \) marks the incident angle of the sunlight. The water’s surface is depicted as a boundary line, and the index of refraction for the water is provided as 1.33.
### Calculation Field:
- **Number**: [Input field for entering the calculated length of the shadow]
- **Units**: [Dropdown menu for selecting units of measurement]
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