Suppose you are performing experiment in the lab by passing light ray to a slab of geometry of thickness 2-cm which is transparent. The angle made by the light ray through the horizontal surface of the slab is 35-degree. What is the light ray direction of travel in the slab and exiting from the slab? Assume refractive index of glass is 1.5 and air is 1.0.

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**Experiment on Refraction of Light Through a Transparent Slab**

In this experiment, you will pass a light ray through a transparent slab of glass with a thickness of 2 cm. The light ray makes an angle of 35 degrees with the normal as it enters through the horizontal surface of the slab. The objective of the experiment is to determine the direction in which the light travels within the slab and as it exits the slab. 

For this experiment, assume the refractive index of the glass is 1.5 and the refractive index of air is 1.0.

**Procedure:**

1. Align the light source so that the light ray enters the slab at a 35-degree angle to the normal.
2. Observe the change in direction of the light ray as it travels through the slab and exits.
3. Use Snell's Law to calculate the angles of refraction within the slab and upon exiting.

**Theoretical Background:**

Snell's Law is given by:
\[ n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \]

Where:
- \( n_1 \) and \( n_2 \) are the refractive indices of the first and second medium respectively.
- \( \theta_1 \) is the angle of incidence.
- \( \theta_2 \) is the angle of refraction.

**Expected Outcomes and Analysis:**

- Calculate the angle of refraction as the light enters the slab using Snell’s Law.
- Determine how the path of light is altered within the slab.
- Analyze and compare the angle of exit with the initial angle of incidence to understand the effects of refraction. 

This experiment helps demonstrate the principles of refraction and the behavior of light as it moves between different media.
Transcribed Image Text:**Experiment on Refraction of Light Through a Transparent Slab** In this experiment, you will pass a light ray through a transparent slab of glass with a thickness of 2 cm. The light ray makes an angle of 35 degrees with the normal as it enters through the horizontal surface of the slab. The objective of the experiment is to determine the direction in which the light travels within the slab and as it exits the slab. For this experiment, assume the refractive index of the glass is 1.5 and the refractive index of air is 1.0. **Procedure:** 1. Align the light source so that the light ray enters the slab at a 35-degree angle to the normal. 2. Observe the change in direction of the light ray as it travels through the slab and exits. 3. Use Snell's Law to calculate the angles of refraction within the slab and upon exiting. **Theoretical Background:** Snell's Law is given by: \[ n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \] Where: - \( n_1 \) and \( n_2 \) are the refractive indices of the first and second medium respectively. - \( \theta_1 \) is the angle of incidence. - \( \theta_2 \) is the angle of refraction. **Expected Outcomes and Analysis:** - Calculate the angle of refraction as the light enters the slab using Snell’s Law. - Determine how the path of light is altered within the slab. - Analyze and compare the angle of exit with the initial angle of incidence to understand the effects of refraction. This experiment helps demonstrate the principles of refraction and the behavior of light as it moves between different media.
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