Part A What is the pH of a buffer prepared by adding 0.708 mol of the weak acid HA to 0.608 mol of NaA in 2.00 L of solution? The dissociation constant K, of HA is 5.66 x 10-7. Express the pH numerically to three decimal places. ▸ View Available Hint(s) pH = 6.181 Submit Correct Since both the acid and base exist in the same volume, we can skip the concentration calculations and use the number of moles in the Henderson- Hasselbalch equation to calculate the pH. The answer will be the same. Part B Previous Answers What is the pH after 0.150 mol of HC1 is added to the buffer from Part A? Assume no volume change on the addition of the acid. Express the pH numerically to three decimal places. ▸ View Available Hint(s) 195| ΑΣΦ pH= 6.124 Submit Previous Answers Request Answer * Incorrect; Try Again; 5 attempts remaining

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Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.148QP
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Part A
What is the pH of a buffer prepared by adding 0.708 mol of the weak acid HA to 0.608 mol of Na.A in 2.00 L of solution? The dissociation constant K of HA is
5.66 x 10-7.
Express the pH numerically to three decimal places.
▸ View Available Hint(s)
pH = 6.181
Submit
Previous Answers
Correct
Since both the acid and base exist in the same volume, we can skip the concentration calculations and use the number of moles in the Henderson-
Hasselbalch equation to calculate the pH. The answer will be the same.
Part B
What is the pH after 0.150 mol of HCl is added to the buffer from Part A? Assume no volume change on the addition of the acid.
Express the pH numerically to three decimal places.
▸ View Available Hint(s)
195| ΑΣΦ
pH= 6.124
Submit Previous Answers Request Answer
* Incorrect; Try Again; 5 attempts remaining
Transcribed Image Text:Part A What is the pH of a buffer prepared by adding 0.708 mol of the weak acid HA to 0.608 mol of Na.A in 2.00 L of solution? The dissociation constant K of HA is 5.66 x 10-7. Express the pH numerically to three decimal places. ▸ View Available Hint(s) pH = 6.181 Submit Previous Answers Correct Since both the acid and base exist in the same volume, we can skip the concentration calculations and use the number of moles in the Henderson- Hasselbalch equation to calculate the pH. The answer will be the same. Part B What is the pH after 0.150 mol of HCl is added to the buffer from Part A? Assume no volume change on the addition of the acid. Express the pH numerically to three decimal places. ▸ View Available Hint(s) 195| ΑΣΦ pH= 6.124 Submit Previous Answers Request Answer * Incorrect; Try Again; 5 attempts remaining
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