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Calculate the pH of the following: 5) A solution that contains 0.10 M ammonium hydrochloride and 0.010 M HCl

Calculate the pH of the following: 5) A solution that contains 0.10 M ammonium hydrochloride and 0.010 M HCl

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the pH of the following:

5) A solution that contains 0.10 M ammonium hydrochloride and 0.010 M HCl

Name Structure K, Acetic acid CH,CO,H 4.756 1.75 x 10-5 (ethanoic acid) NH Alaninc CHCH, 2.344 (CO,H) 9.868 (NH,) 4.53 X 10-3 CO,H 1.36 X 10-10 Aminobenzene - NH 4.601 2.51 X 10-5 (aniline) 4-Aminobenzenesulfonic acid (sulfanilic acid) - NH 3.232 5.86 x 10-4 NH 2-Aminobenzoic acid 2.08 (CO,H) 4.96 (NH,) 8.3 X 10-3 1.10 x 10-s (anthranilic acid) CO,H 2-Aminocthanethiol (2-mercaptoethylamine) HSCH,CH,NH; 8.21 (SH) (u = 0.1) 10.73 (NH,) (p = 0.1) 6.2 x 10-9 1.86 X 10-11 2-Aminocthanol HOCH,CH,NH 9.498 3.18 X 10-10 (ethanolamine) 4.70 (NH3) (20°) 9.97 (OH) (20°) 2.0 X 10-3 1.05 x 10-10 2-Aminophenol `NH Ammonia NH 9.245 5.69 х 10-10 NH NH CHCH,CH,CH,NHC 1.823 (CO,H) 8.991 (NH,) (12.1) (NH,) ( = 0.1) 1.50 x 10-2 Arginine 1.02 X 10-9 8 x 10-13 NH, 2.31 4.9 x 10-3 8.9 x 10-8 1.3 x 10-12 Arsenic acid но-As — ОН 7.05 (hydrogen arsenate) 11.9 OH Arsenious acid As(OH); 9.29 5.1 X 10-10 (hydrogen arsenite) NH: 0 || CHCH,CNH, co,H Asparagine 2.16 (CO,H) (р. %3D0.1) 8.73 (NH;) (µ. - 0.1) 6.9 X 10-3 1.86 x 10-9. *Each acid is written in its protonated form. The acidic protons are indicated in bold type. tpK, values refer to 25°C and zero ionic strength unless otherwise indicated. Values in parentheses are considered to be less reliable. Data are from A. E. MartelI, R. M. Smith, and R. J. Motekaitis, NIST Database 46 (Gaithersburg, MD: National Instinute zdards and Technology, 2001). FT'ne accurate way to calculate K, for the conjugate base is pK, = 13.995 - pK, and K, = 10-pks,
Transcribed Image Text:Name Structure K, Acetic acid CH,CO,H 4.756 1.75 x 10-5 (ethanoic acid) NH Alaninc CHCH, 2.344 (CO,H) 9.868 (NH,) 4.53 X 10-3 CO,H 1.36 X 10-10 Aminobenzene - NH 4.601 2.51 X 10-5 (aniline) 4-Aminobenzenesulfonic acid (sulfanilic acid) - NH 3.232 5.86 x 10-4 NH 2-Aminobenzoic acid 2.08 (CO,H) 4.96 (NH,) 8.3 X 10-3 1.10 x 10-s (anthranilic acid) CO,H 2-Aminocthanethiol (2-mercaptoethylamine) HSCH,CH,NH; 8.21 (SH) (u = 0.1) 10.73 (NH,) (p = 0.1) 6.2 x 10-9 1.86 X 10-11 2-Aminocthanol HOCH,CH,NH 9.498 3.18 X 10-10 (ethanolamine) 4.70 (NH3) (20°) 9.97 (OH) (20°) 2.0 X 10-3 1.05 x 10-10 2-Aminophenol `NH Ammonia NH 9.245 5.69 х 10-10 NH NH CHCH,CH,CH,NHC 1.823 (CO,H) 8.991 (NH,) (12.1) (NH,) ( = 0.1) 1.50 x 10-2 Arginine 1.02 X 10-9 8 x 10-13 NH, 2.31 4.9 x 10-3 8.9 x 10-8 1.3 x 10-12 Arsenic acid но-As — ОН 7.05 (hydrogen arsenate) 11.9 OH Arsenious acid As(OH); 9.29 5.1 X 10-10 (hydrogen arsenite) NH: 0 || CHCH,CNH, co,H Asparagine 2.16 (CO,H) (р. %3D0.1) 8.73 (NH;) (µ. - 0.1) 6.9 X 10-3 1.86 x 10-9. *Each acid is written in its protonated form. The acidic protons are indicated in bold type. tpK, values refer to 25°C and zero ionic strength unless otherwise indicated. Values in parentheses are considered to be less reliable. Data are from A. E. MartelI, R. M. Smith, and R. J. Motekaitis, NIST Database 46 (Gaithersburg, MD: National Instinute zdards and Technology, 2001). FT'ne accurate way to calculate K, for the conjugate base is pK, = 13.995 - pK, and K, = 10-pks,
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