Imagine that you are in chemistry lab and need to make 1.00 LL of a solution with a pH of 2.70. You have in front of you 100 mLmL of 7.00×10−2 MM HClHCl, 100 mLmL of 5.00×10−2 MM NaOHNaOH, and plenty of distilled water. You start to add HClHCl to a beaker of water when someone asks you a question. When you return to your dilution, you accidentally grab the wrong cylinder and add some NaOHNaOH. Once you realize your error, you assess the situation. You have 80.0 mLmL of HClHCl and 90.0 mLmL of NaOHNaOH left in their original containers. Assuming the final solution will be diluted to 1.00 LL , how much more HClHCl should you add to achieve the desired pH? three sig figs pls
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Imagine that you are in chemistry lab and need to make 1.00 LL of a solution with a pH of 2.70.
You have in front of you
- 100 mLmL of 7.00×10−2 MM HClHCl,
- 100 mLmL of 5.00×10−2 MM NaOHNaOH, and
- plenty of distilled water.
You start to add HClHCl to a beaker of water when someone asks you a question. When you return to your dilution, you accidentally grab the wrong cylinder and add some NaOHNaOH. Once you realize your error, you assess the situation. You have 80.0 mLmL of HClHCl and 90.0 mLmL of NaOHNaOH left in their original containers.
Assuming the final solution will be diluted to 1.00 LL , how much more HClHCl should you add to achieve the desired pH?
three sig figs pls
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