▼Part ATwo blocks, each of mass m = 7.60 kg, are connected by a massless rope and start sliding down a slope of incline 0= 40.0° at t = 0.000 s. The slope's top portion is arough surface whose coefficient of kinetic friction is μ = 0.350. At a distance d = 1.40 m from block A's initial position the slope becomes frictionless. (Figure 1)What isthe velocity of the blocks when block A reaches this frictional transition point? Assume that the blocks' width is negligible.Express your answer numerically in meters per second to four significant figures.► View Available Hint(s)V=||| ΑΣΦSubmitPart B Complete previous part(s)Part C Complete previous part(s)HProvide FeedbackrOvec?m/sCReviewU ENG ☎4xNext >7:49 PM7/12/2022 Principle of Linear Impulse and Momentum for a System ofsystem, yieldsΣmi(vi), + Σ/ F, dt = Emi(vi)2where m, is the ith particle's mass, v, is the ith particle's velocity,and F; is the external force that acts on the ith particle. Thisrelationship states that the sum of the initial linear momenta, at timet₁, and the impulses of all the external forces acting between times t₁and t2 is equal to the sum of the linear momenta of the system, at timeto. If the system has a mass center, G, the expression becomesm(ve)₁ + Σ ſt² F; dt = m(vc)2This expression allows the principle of linear impulse and momentumto be applied to a system of particles that is represente as a singleparticle.Figureyxd-1 of 1ParPartProvi

Answered: Image /qna-images/answer/9541bf3b-cdab-46e6-bc72-8edb6e8d35cb.jpg

▼ Part A Two blocks, each of mass m = 7.60 kg, are connected by a massless rope and start sliding down a slope of incline 0= 40.0° at t=0.000 s. The slope's top portion is a rough surface whose coefficient of kinetic friction is x=0.350. At a distance d = 1.40 m from block A's initial position the slope becomes frictionless. (Figure 1)What is the velocity of the blocks when block A reaches this frictional transition point? Assume that the blocks' width is negligible. Express your answer numerically in meters per second to four significant figures. ► View Available Hint(s) V= 195 ΑΣΦ Submit vec 3 ? m/s

▼ Part A Two blocks, each of mass m = 7.60 kg, are connected by a massless rope and start sliding down a slope of incline 0= 40.0° at t=0.000 s. The slope's top portion is a rough surface whose coefficient of kinetic friction is x=0.350. At a distance d = 1.40 m from block A's initial position the slope becomes frictionless. (Figure 1)What is the velocity of the blocks when block A reaches this frictional transition point? Assume that the blocks' width is negligible. Express your answer numerically in meters per second to four significant figures. ► View Available Hint(s) V= 195 ΑΣΦ Submit vec 3 ? m/s

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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Question

▼
Part A
Two blocks, each of mass m = 7.60 kg, are connected by a massless rope and start sliding down a slope of incline 0= 40.0° at t = 0.000 s. The slope's top portion is a
rough surface whose coefficient of kinetic friction is μ = 0.350. At a distance d = 1.40 m from block A's initial position the slope becomes frictionless. (Figure 1)What is
the velocity of the blocks when block A reaches this frictional transition point? Assume that the blocks' width is negligible.
Express your answer numerically in meters per second to four significant figures.
► View Available Hint(s)
V=
||| ΑΣΦ
Submit
Part B Complete previous part(s)
Part C Complete previous part(s)
H
Provide Feedback
r
O
vec
?
m/s
C
Review
U ENG ☎4x
Next >
7:49 PM
7/12/2022

Principle of Linear Impulse and Momentum for a System of
system, yields
Σmi(vi), + Σ/ F, dt = Emi(vi)2
where m, is the ith particle's mass, v, is the ith particle's velocity,
and F; is the external force that acts on the ith particle. This
relationship states that the sum of the initial linear momenta, at time
t₁, and the impulses of all the external forces acting between times t₁
and t2 is equal to the sum of the linear momenta of the system, at time
to. If the system has a mass center, G, the expression becomes
m(ve)₁ + Σ ſt² F; dt = m(vc)2
This expression allows the principle of linear impulse and momentum
to be applied to a system of particles that is represente as a single
particle.
Figure
y
x
d-
1 of 1
Par
Part
Provi

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2) Figure 3 illustrates a first block having mass M1 positioned on a horizontal tabletop. The contacting surfaces between the 1st block and the tabletop have a coefficient of kinetic friction Uk. An ideal rope extends horizontally from the 1st block to an ideal pulley and then vertically downward to a 2nd block having mass M2. Initially, the 2nd block is traveling downward with speed Vo. At some later time, the 2nd block has been displaced a distance H and its speed is Vf. Rope Pulley M, Friction M, Figure 3 Determine expressions {M1, M2, Hk, H, g, Vo} for the following: H (a) Work done by gravity onto the system of 2 blocks; (b) Work done by the normal force onto the system of 2 blocks; (c) Work done by tension onto the system of 2 blocks; and (d) final speed, Vt.
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5 Problem A box of mass m = 50kg is at rest when suddenly a force P is applied. Determine the acceleration if (a) P = 0, (b) P = 150 N, and (c) P = 300 N. The incline has a slope 0 = 15 deg and static coefficient of friction of μs = 0.2 and kinetic coefficient of friction of μk=0.15. Hint: To solve this problem we must first determine if the box is moving or not (to decide if we should use the static or kinetic friction coefficient). You can use the following approach. First assume the friction force has a magnitude Ff and solve for the Ff (as a function of P, g, and 0) under the assumption that the box not moving (i.e., the forces sum to zero along the direction of the ramp). If the Ff you find is less than the maximum static friction force, Ff ≤ μsN, then the box is indeed stationary. If |Fƒ| > 1,N then the static friction force required is too large and the box moves. In this case Ff μKN and the forces are nonzero. Note that friction can act in both directons (up or down the ramp)…
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