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Part A The metabolism of glucose, CH1206. yields carbon dioxide, CO2(g), and water, H2O(1), as products. Energy released in this metabolic process is converted to useful work, w, with about 67.0 % efficiency. The formula for work is Calculate the mass of glucose metabolized by a 83.0 kg person in climbing a mountain with an elevation gain of 1470 m. Assume that the work performed in the climb is four times that required to simply lift 83.0 kg by 1470 m. w = mdg Express your answer to three significant figures and include the appropriate units. where m is mass, d is distance, and g=9.81 m -s2 is the acceleration due to gravity. > View Available Hint(s) Use the data below to answer questions about the metabolism of glucose. ? ΔΗ (kJ/mol) Substance Value Units CO2 (g) -393.5 C,H12O6(s) -1273.3 Submit H2O(1) -285.8 O2(g)

Part A The metabolism of glucose, CH1206. yields carbon dioxide, CO2(g), and water, H2O(1), as products. Energy released in this metabolic process is converted to useful work, w, with about 67.0 % efficiency. The formula for work is Calculate the mass of glucose metabolized by a 83.0 kg person in climbing a mountain with an elevation gain of 1470 m. Assume that the work performed in the climb is four times that required to simply lift 83.0 kg by 1470 m. w = mdg Express your answer to three significant figures and include the appropriate units. where m is mass, d is distance, and g=9.81 m -s2 is the acceleration due to gravity. > View Available Hint(s) Use the data below to answer questions about the metabolism of glucose. ? ΔΗ (kJ/mol) Substance Value Units CO2 (g) -393.5 C,H12O6(s) -1273.3 Submit H2O(1) -285.8 O2(g)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Part A The metabolism of glucose, C6 H12O6, yields carbon dioxide, CO2 (g), and water, H2O(1), as products. Energy released in this metabolic process is converted to useful work, w, with about 67.0 % efficiency. The formula for work is Calculate the mass of glucose metabolized by a 83.0 kg person in climbing a mountain with an elevation gain of 1470 m. Assume that the work performed in the climb is four times that required to simply lift 83.0 kg by 1470 m . W = mdg Express your answer to three significant figures and include the appropriate units. where m is mass, d is distance, and g = 9.81 m · s2 is the acceleration due to gravity. • View Available Hint(s) Use the data below to answer questions about the metabolism of glucose. µA ΔΗ (kJ/mol) Substance Value Units CO2 (g) -393.5 C6 H12O6 (s) -1273.3 Submit H2O(1) O2 (g) -285.8 Provide Feedback Next >
Transcribed Image Text:Part A The metabolism of glucose, C6 H12O6, yields carbon dioxide, CO2 (g), and water, H2O(1), as products. Energy released in this metabolic process is converted to useful work, w, with about 67.0 % efficiency. The formula for work is Calculate the mass of glucose metabolized by a 83.0 kg person in climbing a mountain with an elevation gain of 1470 m. Assume that the work performed in the climb is four times that required to simply lift 83.0 kg by 1470 m . W = mdg Express your answer to three significant figures and include the appropriate units. where m is mass, d is distance, and g = 9.81 m · s2 is the acceleration due to gravity. • View Available Hint(s) Use the data below to answer questions about the metabolism of glucose. µA ΔΗ (kJ/mol) Substance Value Units CO2 (g) -393.5 C6 H12O6 (s) -1273.3 Submit H2O(1) O2 (g) -285.8 Provide Feedback Next >
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