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Part A The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k = Ae E/RT where Ris the gas constant (8.314 J/mol - K), A is a constant called the frequency factor, and E, is the activation energy for the reaction. The activation energy of a certain reaction is 36.3 kJ/mol. At 22 °C, the rate constant is 0.0180s. At what temperature in degrees Celsius would this reaction go twice as t Express your answer with the appropriate units. However, a more practical form of this equation is In 3(뉴 ) T = Value Units which is mathmatically equivalent to where ki and kz are the rate constants for a single reaction at two different absolute temperatures (T and T2). Part B Given that the initial rate constant is 0.0180s at an initial temperature of 22 °C, what would the rate constant be at a temperature of 140. °C for the same reaction described Express your answer with the appropriate units. kz = Value Units Submit Request Answer

Part A The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k = Ae E/RT where Ris the gas constant (8.314 J/mol - K), A is a constant called the frequency factor, and E, is the activation energy for the reaction. The activation energy of a certain reaction is 36.3 kJ/mol. At 22 °C, the rate constant is 0.0180s. At what temperature in degrees Celsius would this reaction go twice as t Express your answer with the appropriate units. However, a more practical form of this equation is In 3(뉴 ) T = Value Units which is mathmatically equivalent to where ki and kz are the rate constants for a single reaction at two different absolute temperatures (T and T2). Part B Given that the initial rate constant is 0.0180s at an initial temperature of 22 °C, what would the rate constant be at a temperature of 140. °C for the same reaction described Express your answer with the appropriate units. kz = Value Units Submit Request Answer

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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please answer all as they are part of 1 question but different questions,,.

Part A The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as The activation energy of a certain reaction is 36.3 kJ/mol . At 22 °C , the rate constant is 0.0180s¬1 . At what temperature in degrees Celsius would this reaction go twice as fast? k = Ae-Ea/RT where R is the gas constant (8.314 J/mol · K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. Express your answer with the appropriate units. However, a more practical form of this equation is HA ? In=( -) k2 k1 Ea 1 1 R T T, which is mathmatically equivalent to T, = Value Units k1 E. In k2 T T R where ki and k2 are the rate constants for a single reaction at two different absolute temperatures (T1 and T2 ). Part B Given that the initial rate constant is 0.0180s- at an initial temperature of 22 °C, what would the rate constant be at a temperature of 140. °C for the same reaction described in Part A? Express your answer with the appropriate units. ? k2 = Value Units Submit Request Answer
Transcribed Image Text:Part A The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as The activation energy of a certain reaction is 36.3 kJ/mol . At 22 °C , the rate constant is 0.0180s¬1 . At what temperature in degrees Celsius would this reaction go twice as fast? k = Ae-Ea/RT where R is the gas constant (8.314 J/mol · K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. Express your answer with the appropriate units. However, a more practical form of this equation is HA ? In=( -) k2 k1 Ea 1 1 R T T, which is mathmatically equivalent to T, = Value Units k1 E. In k2 T T R where ki and k2 are the rate constants for a single reaction at two different absolute temperatures (T1 and T2 ). Part B Given that the initial rate constant is 0.0180s- at an initial temperature of 22 °C, what would the rate constant be at a temperature of 140. °C for the same reaction described in Part A? Express your answer with the appropriate units. ? k2 = Value Units Submit Request Answer
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