Part A Rotational Kinetic Energy: A solid uniform disk of diameter 3.20 m and mass 42 kg rolls without slipping to the bottom of a hill, starting from rest. If the angular speed of the disk is 4.27 rad/s at the bottom, how high did it start on the hill? O 4.28 m O 3.57 m 3.14 m O 2.68 m Submit Request Answer
Angular speed, acceleration and displacement
Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.
Angular Position
Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.
This HW question I have been trying to figure out for so long, please help!
![**Rotational Kinetic Energy Problem**
**Part A**
A solid uniform disk of diameter 3.20 m and mass 42 kg rolls without slipping to the bottom of a hill, starting from rest. If the angular speed of the disk is 4.27 rad/s at the bottom, how high did it start on the hill?
**Options:**
- 4.28 m
- 3.57 m
- 3.14 m
- 2.68 m
*Select the correct option and submit your answer.*
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**Request Answer** [Link]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd9160c0a-0f17-43b1-9fe4-5f497fa2cff6%2Fd0a8c33c-4cb1-4e76-838a-536ec17ccc46%2F68bi14r_processed.png&w=3840&q=75)
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