a) Which of the following equations is an accurate Kirchoff Junction equation for the circuit shows? O 13 + 12 = I1 O 1₁ + 12 = 13 O I₁ + 13 = 12 O None of the above b) Which of the following equations is an accurate Kirchoff Loop equation for the circuit shows? O -₁ -11R₁ - 13R3 - 2 = 0 O1I1R₁13R3 - 2 = 0 O-₁-11R₁ - I3R3 + 2 = 0 O E1I1R₁ + I3R3 - 2 = 0 O E₁I1R₁ - I3R3 + 2 = 0 c) What is the current through resistor R₁? Amps

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Chapter1: Units, Trigonometry. And Vectors
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I dont understand, nned help with all of them. 

Ei
Resistors have values of:
R₁ = 80 Ohm
R₂
R3 = 8 Ohm
R4 = 35 Ohm
= 220 Ohm
R₁
Iz te k
d
H
R₂
win
Ez
Consider the circuit shown in the figure, which has three batteries and four resistors. Use the current arrows and labels in solving this problem.
The batteries are oriented as shown in the drawing. The battery voltages are
E1= 6.00 Volts.
E2 = 18.00 Volts.
E3 19.00 Volts.
I2
Ry
um
c) What is the current through resistor R₁?
Ez
a) Which of the following equations is an accurate Kirchoff Junction equation for the circuit shows?
13 + 12 = 11
O I1 + 12 = 13
O I1 + 13 = 12
O None of the above
b) Which of the following equations is an accurate Kirchoff Loop equation for the circuit shows?
-1 - I₁R₁ - I3R3 - 2 = 0
E₁ - I₁R₁ - I3R3 - 2 = 0
-E1I1R₁ - I3R3 + 2 = 0
E₁ - I₁R₁ + I3R3 - 2 = 0
O E1 - I₁R₁ - 13R3 + 2 = 0
Amps
Transcribed Image Text:Ei Resistors have values of: R₁ = 80 Ohm R₂ R3 = 8 Ohm R4 = 35 Ohm = 220 Ohm R₁ Iz te k d H R₂ win Ez Consider the circuit shown in the figure, which has three batteries and four resistors. Use the current arrows and labels in solving this problem. The batteries are oriented as shown in the drawing. The battery voltages are E1= 6.00 Volts. E2 = 18.00 Volts. E3 19.00 Volts. I2 Ry um c) What is the current through resistor R₁? Ez a) Which of the following equations is an accurate Kirchoff Junction equation for the circuit shows? 13 + 12 = 11 O I1 + 12 = 13 O I1 + 13 = 12 O None of the above b) Which of the following equations is an accurate Kirchoff Loop equation for the circuit shows? -1 - I₁R₁ - I3R3 - 2 = 0 E₁ - I₁R₁ - I3R3 - 2 = 0 -E1I1R₁ - I3R3 + 2 = 0 E₁ - I₁R₁ + I3R3 - 2 = 0 O E1 - I₁R₁ - 13R3 + 2 = 0 Amps
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