Part A Review I Constants A 5000 kg truck is parked on a 7.0° slope. How big is the frictio truck? Express your answer with the appropriate units.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
### Physics Problem Explanation

**Problem Statement:**  
A 5000 kg truck is parked on a 7.0° slope. How big is the friction force on the truck? Express your answer with the appropriate units.

**Solution Steps:**

To solve this problem, we need to determine the frictional force acting on the truck that is preventing it from sliding down the slope. This is a classic static friction problem involving forces on an inclined plane. Here are the steps you would follow:

1. **Identify the Forces Acting on the Truck:**
   - The gravitational force (weight) acting vertically downward: \( F_g = mg \)
     - Where \( m \) is the mass of the truck (5000 kg)
     - \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \))
   - The normal force perpendicular to the slope.
   - The frictional force parallel to the slope, preventing the truck from moving.

2. **Calculate the Gravitational Force:**
   \[
   F_g = m \cdot g = 5000 \, \text{kg} \times 9.81 \, \text{m/s}^2 = 49050 \, \text{N}
   \]

3. **Determine the Components of the Gravitational Force:**
   - Parallel to the slope: \( F_{g, \parallel} = F_g \sin(\theta) \)
   - Perpendicular to the slope: \( F_{g, \perp} = F_g \cos(\theta) \)

4. **Calculate the Parallel Component:**
   \[
   F_{g, \parallel} = 49050 \, \text{N} \times \sin(7.0^\circ)
   \]
   Using \( \sin(7.0^\circ) \approx 0.1219 \)
   \[
   F_{g, \parallel} = 49050 \, \text{N} \times 0.1219 \approx 5977 \, \text{N}
   \]

5. **Static Frictional Force:**
   - For a vehicle parked on a slope, the static frictional force must be equal and opposite to the component of the gravitational force parallel to the slope to prevent movement.

So, the magnitude of the friction force \(
Transcribed Image Text:### Physics Problem Explanation **Problem Statement:** A 5000 kg truck is parked on a 7.0° slope. How big is the friction force on the truck? Express your answer with the appropriate units. **Solution Steps:** To solve this problem, we need to determine the frictional force acting on the truck that is preventing it from sliding down the slope. This is a classic static friction problem involving forces on an inclined plane. Here are the steps you would follow: 1. **Identify the Forces Acting on the Truck:** - The gravitational force (weight) acting vertically downward: \( F_g = mg \) - Where \( m \) is the mass of the truck (5000 kg) - \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)) - The normal force perpendicular to the slope. - The frictional force parallel to the slope, preventing the truck from moving. 2. **Calculate the Gravitational Force:** \[ F_g = m \cdot g = 5000 \, \text{kg} \times 9.81 \, \text{m/s}^2 = 49050 \, \text{N} \] 3. **Determine the Components of the Gravitational Force:** - Parallel to the slope: \( F_{g, \parallel} = F_g \sin(\theta) \) - Perpendicular to the slope: \( F_{g, \perp} = F_g \cos(\theta) \) 4. **Calculate the Parallel Component:** \[ F_{g, \parallel} = 49050 \, \text{N} \times \sin(7.0^\circ) \] Using \( \sin(7.0^\circ) \approx 0.1219 \) \[ F_{g, \parallel} = 49050 \, \text{N} \times 0.1219 \approx 5977 \, \text{N} \] 5. **Static Frictional Force:** - For a vehicle parked on a slope, the static frictional force must be equal and opposite to the component of the gravitational force parallel to the slope to prevent movement. So, the magnitude of the friction force \(
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Knowledge Booster
Free body diagram
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON