Problem 6.20 - Enhanced - with Feedback A wind turbine has 12,000 kg blades that are 41 m long. The blades spin at 24 rpm. Part A If we model a blade as a point mass at
Problem 6.20 - Enhanced - with Feedback A wind turbine has 12,000 kg blades that are 41 m long. The blades spin at 24 rpm. Part A If we model a blade as a point mass at
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem 6.20 - Enhanced - with Feedback**
**Part A**
A wind turbine has \( 12,000 \, \text{kg} \) blades that are \( 41 \, \text{m} \) long. The blades spin at \( 24 \, \text{rpm} \).
---
In this section, we will analyze the properties and dynamics of the wind turbine blades. The turbines under examination have significant mass and length, making their rotational characteristics and the forces acting upon them crucial for understanding their operation and performance.
1. Blade Mass: \( 12,000 \, \text{kg} \)
2. Blade Length: \( 41 \, \text{m} \)
3. Rotation Speed: \( 24 \, \text{rpm} \) (revolutions per minute)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2769bbd1-f3e5-43dc-9507-f39267f06cfb%2F4ea8646e-ff1d-4ab3-88f7-bd059a0b6259%2F3th5kys_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 6.20 - Enhanced - with Feedback**
**Part A**
A wind turbine has \( 12,000 \, \text{kg} \) blades that are \( 41 \, \text{m} \) long. The blades spin at \( 24 \, \text{rpm} \).
---
In this section, we will analyze the properties and dynamics of the wind turbine blades. The turbines under examination have significant mass and length, making their rotational characteristics and the forces acting upon them crucial for understanding their operation and performance.
1. Blade Mass: \( 12,000 \, \text{kg} \)
2. Blade Length: \( 41 \, \text{m} \)
3. Rotation Speed: \( 24 \, \text{rpm} \) (revolutions per minute)
![### Educational Resource: Understanding Centripetal Force
#### Part A
**Problem Statement:**
If we model a blade as a point mass at the midpoint of the blade, what is the inward force necessary to provide each blade's centripetal acceleration?
**Instructions for Students:**
Express your answer with the appropriate units.
**Answer Format:**
\[ F = \text{Value} \: \text{Units} \]
**Input Tools:**
- **Square Root Button (√)**
- **Square Button (x²)**
- **Unit Selector**
- **Clear Button (↻)**
- **Help Button (?)**
**Explanation:**
This problem requires students to calculate the inward (centripetal) force needed to keep a blade, modeled as a point mass at its midpoint, in circular motion. The centripetal force is necessary to provide the required centripetal acceleration, keeping the blade moving in a circular path.
When answering, make sure to:
1. Calculate the value of the centripetal force using the given parameters.
2. Use the correct units to express your force value.
**Formula Reminder:**
The centripetal force \( F \) can be calculated using the formula:
\[ F = m \cdot a_c \]
where
\( m \) = mass of the point (blade),
\( a_c \) = centripetal acceleration.
For reference, centripetal acceleration \( a_c \) is given by:
\[ a_c = \frac{v^2}{r} \]
where
\( v \) = velocity,
\( r \) = radius of the circular path.
Or alternatively:
\[ a_c = r \cdot \omega^2 \]
where
\( \omega \) = angular velocity.
Students should verify their units and ensure that the calculation matches the physical context of the problem.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2769bbd1-f3e5-43dc-9507-f39267f06cfb%2F4ea8646e-ff1d-4ab3-88f7-bd059a0b6259%2F5udun6n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Educational Resource: Understanding Centripetal Force
#### Part A
**Problem Statement:**
If we model a blade as a point mass at the midpoint of the blade, what is the inward force necessary to provide each blade's centripetal acceleration?
**Instructions for Students:**
Express your answer with the appropriate units.
**Answer Format:**
\[ F = \text{Value} \: \text{Units} \]
**Input Tools:**
- **Square Root Button (√)**
- **Square Button (x²)**
- **Unit Selector**
- **Clear Button (↻)**
- **Help Button (?)**
**Explanation:**
This problem requires students to calculate the inward (centripetal) force needed to keep a blade, modeled as a point mass at its midpoint, in circular motion. The centripetal force is necessary to provide the required centripetal acceleration, keeping the blade moving in a circular path.
When answering, make sure to:
1. Calculate the value of the centripetal force using the given parameters.
2. Use the correct units to express your force value.
**Formula Reminder:**
The centripetal force \( F \) can be calculated using the formula:
\[ F = m \cdot a_c \]
where
\( m \) = mass of the point (blade),
\( a_c \) = centripetal acceleration.
For reference, centripetal acceleration \( a_c \) is given by:
\[ a_c = \frac{v^2}{r} \]
where
\( v \) = velocity,
\( r \) = radius of the circular path.
Or alternatively:
\[ a_c = r \cdot \omega^2 \]
where
\( \omega \) = angular velocity.
Students should verify their units and ensure that the calculation matches the physical context of the problem.
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