pls.p helpp partb Part AGibbs energy change, A. G°, is related to cell potential, Eell, by theequationA;G° = –nFE ellCalculate the standard Gibbs energy change at 25 °C for the following reaction:Mg(s) + Fe2+(ag)→Mg²+(ag) +Fe(s)where n is the number of moles of electrons transferred andF = 96 500 C mol-1 is the Faraday's constant.Express your answer to three significant figures and include the appropriate units.A¡G° = -371 kJ.mol-1SubmitPrevious AnswersCorrectSince Eel is positive and A, G° is negative, this reaction is spontaneous under standard conditions.Part BCalculate the standard cell potential at 25 °C for the reactionX(s) + 2Y* (ag)→X²+(ag) +2Y(s)where A, H° = -825 kJ mol-1and Ar S° = -147 J K-1 mol-1.Express your answer to three significant figures and include the appropriate units.HA?E celValueUnitsSubmitRequest Answer

on A‚G° = -nFEel Calculate the standard Gibbs energy change at 25 °C for the following reaction: Mg(s) + Fe²+(aq)→Mg²+(aq) +Fe(s) n is the number of moles of electrons transferred and 96 500 C mol¬1 is the Faraday's constant. Express your answer to three significant figures and include the appropriate units. A;G® = -371 kJ•mol-! Submit Previous Answers v Correct Since E is positive and A,G° is negative, this reaction is spontaneous under standard conditions. Part B Calculate the standard cell potential at 25 °C for the reaction X(s) +2Y*(aq)→X²*(aq) + 2Y(s) where A, H° = -825 kJ mol-1 and A, S° = -147 JK-' mol¯! Express your answer to three significant figures and include the appropriate units. Eell = Value Units Submit Request Answer