Part AEstimate the value of the equilibrium constant at520 K for each of the following reactions.2C0(g) + O2(9) = 2CO2(g)Ηνα ΑΣφK = 4.72 • 10SubmitPrevious Answers Request AnswerX Incorrect; Try Again; 5 attempts remainingPart B2H2 S(g) = 2H2 (g) + S2(g)ΑΣφ?K =SubmitRequest Answer

Answered: Image /qna-images/answer/1acc5edb-ffcf-477f-bdcf-e6b693c57172.jpg

Part A Estimate the value of the equilibrium constant at 520 K for each of the following reactions. 2C0(g) + 02 (9) = 2CO2 (9) K = 4.72 • 10° Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part B 2H2S(g) = 2H2 (9) + S2(9) ΑΣφ ? K = Submit Request Answer

Part A Estimate the value of the equilibrium constant at 520 K for each of the following reactions. 2C0(g) + 02 (9) = 2CO2 (9) K = 4.72 • 10° Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part B 2H2S(g) = 2H2 (9) + S2(9) ΑΣφ ? K = Submit Request Answer

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter13: Chemical Equilibrium

Section: Chapter Questions

Problem 6RQ: Distinguish between the terms equilibrium constant and reaction quotient. When Q = K, what does this...

See similar textbooks

Similar questions

7-40 Is there any change in conditions that change the equilibrium constant, K, of a given reaction?
At a certain temperature, K=0.29 for the decomposition of two moles of iodine trichloride, ICl3(s), to chlorine and iodine gases. The partial pressure of chlorine gas at equilibrium is three times that of iodine gas. What are the partial pressures of iodine and chlorine at equilibrium?
For the system SO3(g)SO2(g)+12 O2(g)at 1000 K, K=0.45. Sulfur trioxide, originally at 1.00 atm pressure, partially dissociates to SO2 and O2 at 1000 K. What is its partial pressure at equilibrium?
Consider the equation G = G + RT ln(Q). What is the value of G for a reaction at equilibrium? What does Q equal at equilibrium? At equilibrium, the previous equation reduces to G = RT ln(K). When G 0, what does it indicate about K? When G 0, what does it indicate about K? When t G = 0, what does it indicate about K? G predicts spontaneity for a reaction, whereas G predicts the equilibrium position. Explain what this statement means. Under what conditions can you use G to determine the spontaneity of a reaction?
Answer the following questions regarding the butane isobutane equilibrium (Kc = 2.50 at 298 K). (a) Is the system at equilibrium when [butane] = 0.00097 M and [isobutane] = 0.00218 M? If not, in which direction will the reaction proceed to achieve equilibrium? (b) Is the system at equilibrium when[butane] = 0.00075 M and [isobutane] = 0.00260M? If not, in which direction will the reaction proceed to achieve equilibrium?
7-64 As we shall see in Chapter 20, there are two forms of glucose, designated alpha and betawhich are in equilibrium in aqueous solution. The equilibrium constant for the reaction is 1.5 at 30°C. (a) If you begin with a fresh 1.0 M solution of D-glucose in water, what will be its concentration when equilibrium is reached? (b) Calculate the percentage of glucose and of glucose present at equilibrium in aqueous solution at 30°C.
Consider the following system at equilibrium at 25C: PCl3(g)+Cl(g)PCl5(g)G=92.50KJ What will happen to the ratio of partial pressure of PCl5 to partial pressure of PCI3 if the temperature is raised? Explain completely.
After a mixture of cis-2-butene and trans-2-butene has reached equilibrium at 600 K, where Kc = 1.47, half of the cis-2-butcne is suddenly removed. Answer these questions: (a) Is the new mixture at equilibrium? Explain why or why not. (b) In the new mixture, which rate is faster, cis trans or trans cis? Or are both rates the same? (c) In an equilibrium mixture, which concentration is larger, cis-2-butenc or trans-2-butene? (d) If the concentration of cis-2-butene at equilibrium is 0.10 mol/L, what will be the concentration of trans-2-butene?
Consider the following hypothetical reactions and their equilibrium constants at 75C, 3A(g)3B(g)+2C(g)K1=0.31 3D(g)+2B(g)2C(g)K1=2.8 Find the equilibrium constant at 75C for the following reaction A(g)D(g)+53B(g)
Suppose a reaction has the equilibrium constant K = 1.3 108. What does the magnitude of this constant tell you about the relative concentrations of products and reactants that will be present once equilibrium is reached? Is this reaction likely to be a good source of the products?
The following equilibrium is established in a closed container: C(s)+O2(g)CO2(g)H=393kJmol1 How does the equilibrium shift in response to each of the following stresses? (a) The quantity of solid carbon is increased. (b) A small quantity of water is added, and CO2 dissolves in it. (c) The system is cooled. (d) The volume of the container is increased.
7-32 A particular reaction has an equilibrium constant of 1.13 under one set of conditions and an equilibrium constant of 1.72 under a different set of conditions. Which conditions would be more advantageous in an industrial process that sought to obtain the maximum amount of products? Explain.