Given the chemical reaction (R1) below, calculate the numerical value of the equilibrium constant for reaction R2 (give your answer to three sig figs) (R1) 2 NO(g) + O2<(g) =2 NO2(g); Kc = 1.62 (R2) 6 NO(g) + 3 O2(g) = 6 NO2(g)
Given the chemical reaction (R1) below, calculate the numerical value of the equilibrium constant for reaction R2 (give your answer to three sig figs) (R1) 2 NO(g) + O2<(g) =2 NO2(g); Kc = 1.62 (R2) 6 NO(g) + 3 O2(g) = 6 NO2(g)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter13: Chemical Equilibrium
Section: Chapter Questions
Problem 2ALQ: The boxes shown below represent a set of initial conditions for the reaction: Draw a quantitative...
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![**Chemical Equilibrium Constant Calculation**
**Problem Statement:**
Given the chemical reaction (R1) below, calculate the numerical value of the equilibrium constant for reaction R2 (give your answer to three significant figures).
**Reactions:**
(R1) \(2 \text{NO}(g) + \text{O}_2(g) \rightleftharpoons 2 \text{NO}_2(g); \, K_c = 1.62\)
(R2) \(6 \text{NO}(g) + 3 \text{O}_2(g) \rightleftharpoons 6 \text{NO}_2(g)\)
**Solution Approach:**
Notice that reaction R2 is simply the reaction R1 multiplied by 3. The equilibrium constant for R2 (\(K_{c2}\)) can be calculated using the relationship between the equilibrium constants of reactions that are multiples of each other.
Given \(K_{c1}\) for R1 is 1.62, then:
\[K_{c2} = (K_{c1})^3 = (1.62)^3\]
Calculate the numerical value to get your final answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0259c9da-a893-42a4-9aeb-f2e84d3b7404%2Fd5d61aeb-2f05-4d52-b893-84065e4ea110%2Fz6wms8g_processed.png&w=3840&q=75)
Transcribed Image Text:**Chemical Equilibrium Constant Calculation**
**Problem Statement:**
Given the chemical reaction (R1) below, calculate the numerical value of the equilibrium constant for reaction R2 (give your answer to three significant figures).
**Reactions:**
(R1) \(2 \text{NO}(g) + \text{O}_2(g) \rightleftharpoons 2 \text{NO}_2(g); \, K_c = 1.62\)
(R2) \(6 \text{NO}(g) + 3 \text{O}_2(g) \rightleftharpoons 6 \text{NO}_2(g)\)
**Solution Approach:**
Notice that reaction R2 is simply the reaction R1 multiplied by 3. The equilibrium constant for R2 (\(K_{c2}\)) can be calculated using the relationship between the equilibrium constants of reactions that are multiples of each other.
Given \(K_{c1}\) for R1 is 1.62, then:
\[K_{c2} = (K_{c1})^3 = (1.62)^3\]
Calculate the numerical value to get your final answer.
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