Given the chemical reaction (R1) below, calculate the numerical value of the equilibrium constant for reaction R2 (give your answer to three sig figs) (R1) 2 NO(g) + O2<(g) =2 NO2(g); Kc = 1.62 (R2) 6 NO(g) + 3 O2(g) = 6 NO2(g)

Chemistry
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Chapter13: Chemical Equilibrium
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Problem 2ALQ: The boxes shown below represent a set of initial conditions for the reaction: Draw a quantitative...
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**Chemical Equilibrium Constant Calculation**

**Problem Statement:**

Given the chemical reaction (R1) below, calculate the numerical value of the equilibrium constant for reaction R2 (give your answer to three significant figures).

**Reactions:**

(R1) \(2 \text{NO}(g) + \text{O}_2(g) \rightleftharpoons 2 \text{NO}_2(g); \, K_c = 1.62\)

(R2) \(6 \text{NO}(g) + 3 \text{O}_2(g) \rightleftharpoons 6 \text{NO}_2(g)\)

**Solution Approach:**

Notice that reaction R2 is simply the reaction R1 multiplied by 3. The equilibrium constant for R2 (\(K_{c2}\)) can be calculated using the relationship between the equilibrium constants of reactions that are multiples of each other.

Given \(K_{c1}\) for R1 is 1.62, then:

\[K_{c2} = (K_{c1})^3 = (1.62)^3\]

Calculate the numerical value to get your final answer.
Transcribed Image Text:**Chemical Equilibrium Constant Calculation** **Problem Statement:** Given the chemical reaction (R1) below, calculate the numerical value of the equilibrium constant for reaction R2 (give your answer to three significant figures). **Reactions:** (R1) \(2 \text{NO}(g) + \text{O}_2(g) \rightleftharpoons 2 \text{NO}_2(g); \, K_c = 1.62\) (R2) \(6 \text{NO}(g) + 3 \text{O}_2(g) \rightleftharpoons 6 \text{NO}_2(g)\) **Solution Approach:** Notice that reaction R2 is simply the reaction R1 multiplied by 3. The equilibrium constant for R2 (\(K_{c2}\)) can be calculated using the relationship between the equilibrium constants of reactions that are multiples of each other. Given \(K_{c1}\) for R1 is 1.62, then: \[K_{c2} = (K_{c1})^3 = (1.62)^3\] Calculate the numerical value to get your final answer.
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