Part A Calculate w for the adiabatic expansion of 3.35 mol of an ideal gas at an initial pressure of 1.50 bar from an initial temperature of 430. K to a final temperature of 310. K. Assume that Cp m = 5R/2. Express the work to three significant figures and include the appropriate units. HA ? w = 4595.6 J Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B Choose an expression for the work done in the isothermal reversible expansion of the gas at 310. K from an initial pressure of 1.50 bar. O Wrer = -nCP,m(Pt - Pt) R(P - R) O Wrey = O Wrer =-n(P - R)AT O Wrev =-nRTln Submit Request Answer

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Chapter1: Units, Trigonometry. And Vectors
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Part A
Calculate w for the adiabatic expansion of 3.35 mol of an ideal gas at an initial pressure of 1.50 bar from an initial temperature of 430. K to a final temperature of 310. K. Assume that Cp m = 5R/2.
Express the work to three significant figures and include the appropriate units.
w = 4595.6
J
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 4 attempts remaining
Part B
Choose an expression for the work done in the isothermal reversible expansion of the gas at 310. K from an initial pressure of 1.50 bar
O Wrev = -nCp,m (Pt – Pt)
O Wrev =R(P – R)
O Wrev = -n(P – P)AT
nRTln
Wrev =
Submit
Request Answer
Transcribed Image Text:Part A Calculate w for the adiabatic expansion of 3.35 mol of an ideal gas at an initial pressure of 1.50 bar from an initial temperature of 430. K to a final temperature of 310. K. Assume that Cp m = 5R/2. Express the work to three significant figures and include the appropriate units. w = 4595.6 J Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B Choose an expression for the work done in the isothermal reversible expansion of the gas at 310. K from an initial pressure of 1.50 bar O Wrev = -nCp,m (Pt – Pt) O Wrev =R(P – R) O Wrev = -n(P – P)AT nRTln Wrev = Submit Request Answer
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