P2- 2.0 atm P 0 0 657°C 37°C Isothermal V3 V(L) The figure (not to scale) shows a pV diagram for 1.1 g of helium gas (He) that undergoes the process 123. The ideal gas constant is R = 8.314 J/mol. K = 0.0821 L.atm/mol K, and the atomic weight of helium is 4.0 g/mol. What is the value of V3 in liters? Please give your numerical answer with one decimal place.
P2- 2.0 atm P 0 0 657°C 37°C Isothermal V3 V(L) The figure (not to scale) shows a pV diagram for 1.1 g of helium gas (He) that undergoes the process 123. The ideal gas constant is R = 8.314 J/mol. K = 0.0821 L.atm/mol K, and the atomic weight of helium is 4.0 g/mol. What is the value of V3 in liters? Please give your numerical answer with one decimal place.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:The image presents a pV diagram for 1.1 g of helium gas (He) that undergoes a process from point 1 to point 2 and then to point 3. The diagram illustrates the pressures and volumes at these points as well as the temperatures involved.
- **Axes:**
- The vertical axis represents pressure (p), measured in atmospheres (atm).
- The horizontal axis represents volume (V), measured in liters (L).
- **Points:**
- Point 1 is at 2.0 atm and 37°C.
- Point 2 is at temperature 657°C. This point is on an isothermal curve, meaning it represents a process at constant temperature.
- Point 3 follows the process from point 2.
- **Constants:**
- The ideal gas constant \( R = 8.314 \, \text{J/mol} \cdot \text{K} = 0.0821 \, \text{L} \cdot \text{atm/mol} \cdot \text{K} \).
- Atomic weight of helium is 4.0 g/mol.
The question asks for the value of V3 in liters. The answer should be provided with one decimal place.
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