Problem 1515 of 19ConstantsPart AA current-carrying gold wire has a diameter of0.82 mm. The electric field in the wire is0.51 V/m. Use the resistivity at room temperatureWhat is the current carried by the wire?for gold p = 2.44 × 10-8 N- mExpress your answer with the appropriate units.For related problemsolving tips and strategies, youmay want to view a Video Tutor Solution of Electricfield, potential difference, and resistance in a wire.Tempjetes Symbols undo regdo Tesetkeyboard shortcuts hblpI =ValueUnitsSubmitRequest AnswerPart BWhat is the potential difference between two points in the wire 6.4 m apart?Express your answer with the appropriate units.Tempjetes Symbols undo reglo Teset keyboard shortcuts hblpv= ValueUnitsSubmitRequest Answer• Part CWhat is the resistance of a 6.4 m length of this wire?Express your answer with the appropriate units.Tempjetes Symbols undo regdo Teset keyboard shortcuts helpR = ValueUnitsSubmitRequest AnswerProvide FeedbackNext >

Given data d=0.82 mmρ=2.44×10-8 Ω-mE=0.51 V/m Here, d is the diameter of the wire. E is the electric…

Answered: Part A A current-carrying gold wire has…

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