Part A (1 of 1) Draw the curved arrows for Step 1 of this mechanism. Arrow-pushing Instructions NOC XT H3C. H Check H H-Br: Next H H (1 of 1) CH3 Step 1 H3C. H HH H Br: CH3

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**Title: Understanding the Mechanism of Electrophilic Addition Reaction**

**Part A (1 of 1): Draw the Curved Arrows for Step 1 of this Mechanism**

**Description:**

In this step, we observe the mechanism of an electrophilic addition reaction involving HBr and an alkene.

**Reactants:**

- **Alkene:** The molecule on the left features a double bond between two central carbon atoms. It is a hydrocarbon with the structure: 
  - (CH3)2C=CHCH3, where each carbon is bonded with sufficient hydrogen atoms to satisfy the valency.
  
- **Hydrogen Bromide (HBr):** The hydrogen is bonded to bromine (Br) with a pair of lone electrons on the bromine atom.

**Products:**

- After Step 1, the alkene is converted into a carbocation.
- **Carbocation Formation:** The positive charge is located on one of the central carbon atoms that were part of the original double bond.
- The bromine atom now has a negative charge, depicted with three pairs of lone electrons.

**Mechanism Detail:**

- The double bond in the alkene acts as a nucleophile, attacking the hydrogen atom in HBr.
- This leads to the formation of a new C-H bond and creates a carbocation.
- The bromine atom takes the electrons from the H-Br bond, becoming a bromide ion (\(Br^-\)).

**Instructions:** 

- Use curved arrows to depict the movement of electrons. These arrows convey how electrons are transferred during bond formation and breaking:
  - From the double bond of the alkene to the hydrogen atom of HBr.
  - From the H-Br bond to the bromine atom.

Understanding these electron movements is crucial for grasping the fundamentals of organic reaction mechanisms. Viewers are encouraged to draw the arrows to reinforce the learning process.

**Navigation:**
- Use the "Check" button to confirm your answer, or proceed to the next concept using the "Next" button.
Transcribed Image Text:**Title: Understanding the Mechanism of Electrophilic Addition Reaction** **Part A (1 of 1): Draw the Curved Arrows for Step 1 of this Mechanism** **Description:** In this step, we observe the mechanism of an electrophilic addition reaction involving HBr and an alkene. **Reactants:** - **Alkene:** The molecule on the left features a double bond between two central carbon atoms. It is a hydrocarbon with the structure: - (CH3)2C=CHCH3, where each carbon is bonded with sufficient hydrogen atoms to satisfy the valency. - **Hydrogen Bromide (HBr):** The hydrogen is bonded to bromine (Br) with a pair of lone electrons on the bromine atom. **Products:** - After Step 1, the alkene is converted into a carbocation. - **Carbocation Formation:** The positive charge is located on one of the central carbon atoms that were part of the original double bond. - The bromine atom now has a negative charge, depicted with three pairs of lone electrons. **Mechanism Detail:** - The double bond in the alkene acts as a nucleophile, attacking the hydrogen atom in HBr. - This leads to the formation of a new C-H bond and creates a carbocation. - The bromine atom takes the electrons from the H-Br bond, becoming a bromide ion (\(Br^-\)). **Instructions:** - Use curved arrows to depict the movement of electrons. These arrows convey how electrons are transferred during bond formation and breaking: - From the double bond of the alkene to the hydrogen atom of HBr. - From the H-Br bond to the bromine atom. Understanding these electron movements is crucial for grasping the fundamentals of organic reaction mechanisms. Viewers are encouraged to draw the arrows to reinforce the learning process. **Navigation:** - Use the "Check" button to confirm your answer, or proceed to the next concept using the "Next" button.
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