Part 9 of 10-Analyze Now Jed and Kadia tackle a homework problem: An object of mass m, = 13 kg and velocity v, = 5.5 m/s crashes into another object of mass m, = 6 kg and velocity v2 = -20.5 m/s. The two particles stick together as a result of the collision. Because no external forces are acting, the collision does not change the total momentum of the system of two particles, so the principle of conservation of linear momentum applies. m,V1i + m2V2i = (m, + m2)Vf %3D If Jed and Kadia use the one-dimensional conservation of momentum equation to find the final velocity of the two joined objects after the collision, what do they obtain? (Indicate the direction with the sign of your answer.) -2.71 -2.71 m/s Part 10 of 10 - Analyze Although the forces that the two objects exert on each other cannot change their total momentum, they can change the total kinetic energy in an inelastic collision such as the one being considered. All of the mechanical energy in the problem is kinetic energy. Change in kinetic energy is given by AK = What.do Jed.and Kadia find for the change in the total mechanical energy of the system?

Part 9 of 10-Analyze Now Jed and Kadia tackle a homework problem: An object of mass m, = 13 kg and velocity v, = 5.5 m/s crashes into another object of mass m, = 6 kg and velocity v2 = -20.5 m/s. The two particles stick together as a result of the collision. Because no external forces are acting, the collision does not change the total momentum of the system of two particles, so the principle of conservation of linear momentum applies. m,V1i + m2V2i = (m, + m2)Vf %3D If Jed and Kadia use the one-dimensional conservation of momentum equation to find the final velocity of the two joined objects after the collision, what do they obtain? (Indicate the direction with the sign of your answer.) -2.71 -2.71 m/s Part 10 of 10 - Analyze Although the forces that the two objects exert on each other cannot change their total momentum, they can change the total kinetic energy in an inelastic collision such as the one being considered. All of the mechanical energy in the problem is kinetic energy. Change in kinetic energy is given by AK = What.do Jed.and Kadia find for the change in the total mechanical energy of the system?

Name: **Part 9 of 10 - Analyze**Now Jed and Kadia tackle a homework problem
Uploaded: 2024-03-20T06:57:37.000Z
Channel: Bartleby
Description: **Part 9 of 10 - Analyze**Now Jed and Kadia tackle a homework problem:An object of mass \(m_1 = 13 \, \text{kg}\) and velocity \(\vec{v}_1 = 5.5 \, \text{m/s}\) crashes into another object of mass \(m_2 = 6 \, \text{kg}\) and velocity \(\vec{v}_2 =

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A billiard player sends the cue ball toward a group of three balls that are initially at rest and in contact with one another. After the cue ball strikes the group, the four balls scatter, each traveling in a different direction with different speeds as shown in the figure below. If each ball has the same mass, 0.16 kg, determine the total momentum of the system consisting of the four balls immediately after the collision. (Assume v1 = 0.33 m/s, ?1 = 70°, v2 = 0.49 m/s, ?2 = 30°, v3 = 0.23 m/s, v4 = 0.48 m/s.)
If a mass of 1 kg with an initial velocity of 4 m/s to the right collides elastically with a mass of 3 kg going 1 m/s to the left, what will be the velocity of the first mass after the collision? Right is positive, left is negative. Options include: + 1.0 m/s -2.5 m/s -1.5 m/s -3.5 m/s
A 0.060-kgkg tennis ball, moving with a speed of 5.80 m/sm/s , has a head-on collision with a 0.090-kgkg ball initially moving in the same direction at a speed of 3.48 m/sm/s . Assume that the collision is perfectly elastic. Determine the speed of the 0.090-kgkg ball after the collision. Express your answer to two significant figures and include the appropriate units.
Two pieces of space debris drift toward each other, collide, and stick together. The first piece has a mass of 45 kg and a velocity of m/s just before the collision. The second piece has a mass of 65 kg and a velocity of m/s just before the collision. What is the velocity of their center of mass after the collision? O ( 0.73, 0.73, 4.95 ) m/s O ( 3.27, 3.27, 4.05 ) m/s O ( 9.00, -5.00, 9.00 ) m/s O ( -0.99, -0.99, 11.50 ) m/s O None of the above
The two collars have the masses and initial velocities shown in the figure. The coefficient of restitution for the collision is e=0.5, and friction is negligible. a) Determine the velocity of the two collars after impact. b) If the time duration of the collision is 0.025 s, determine the average impact force. V₁ = 7 m/s V₂ = 5 m/s m₁ = 2 kg m₂ = 3 kg
I need help with question 8?
ent G An impulse of 12.2 kg*m/s is deli x 361242/take 10 p Question 1 A warehouse employee is pushing a 30.0 kg desk across a floor at a constant speed of 0.50 m/s. What is the magnitude of the momentum of the desk? O 0.017 kg*m/s O 15.0 kg*m/s O 60 kg*m/s O 30.5 kg*m/s Question 2 10 pts Norton Antivirus: 19.99/YE Your special price is valid to Google Chrome istudy-helper.co The momentum of a 12kg dog racing to greet its owner has a Norton What is the dog's speed? Install O a Cop
In outer space, far from other objects, two rocks collide and stick together. Before the collision, their momenta were (-10,20,-5) kg⋅m/s and (8,-6,12) kg⋅m/s. What was their total momentum before the collision? What must be the momentum of the combined object after the collision?
Lucy is cruising through space in her new spaceship. As she coasts along, a tiny spacebug drifts into her path and bounces off the window. Consider several statements concerning this scenario. Evaluate each statement according to the law of momentum conservation and match it to the appropriate category. Must be true according to the law of momentum conservation Must be false according to the law of momentum conservation Answer Bank Not determined by the law of momentum conservation If the spacebug had stuck to the spaceship instead of bouncing off, momentum would not have been conserved for this interaction. The change in the spacebug's momentum during the collision is greater than the change in the spaceship's momentum. The total chanaa in momentum for this interaction is nem The total momentum of the spaceship and spacebug before the collision is equal to their total momentum afterward. 日示全部 X
A radioactive nucleus at rest decays into a second nucleus, an electron, and a neutrino. The electron and neutrino are emitted at right angles and have momenta of Pe=9.67x10-23 kg. m/s and p = 5.99×10-23 kg. m/s. respectively. (Figure 1) Figure Pnuc nuc +y 0 Onuc Py Pe 1 of 1 +X Part A Determine the magnitude of the momentum of the second (recoiling) nucleus. Express your answer to three significant figures and include the appropriate units. Pnuc= Submit Part B Onuc = Submit μA 4 Provide Feedback Value Request Answer Determine the angle between the momentum of the electron and the momentum of the second (rec Express your answer using three significant figures. [VE| ΑΣΦ 1 → C Request Answer Units 1 ? ?
INITIAL: FINAL: M. A white billiard ball with mass mw = 1.53 kg is moving directly to the right with a speed of v = 3.25 m/s and collides elastically with a black billiard ball with the same mass mb = 1.53 kg that is initially at rest. The two collide elastically and the white ball ends up moving at an angle above the horizontal of ew = 51° and the black ball ends up moving at an angle below the horizontal of Ob = 39°. %3D 1) What is the final speed of the white ball? m/s Submit 2) What is the final speed of the black ball? m/s Submit
Answer part a, b and c