### Example Physics Problem: Momentum in Collisions#### Question 4-a, Numerical:A small car of mass 1200 kg is moving with an initial velocity \(v_{2i} = +22\) m/s. It collides with the back of a small truck of 8600 kg mass that is moving with an initial velocity \(v_{1i} = +14\) m/s. The velocity of the truck after the collision is 14.2 m/s, as shown in the figure below.**Figure Description:**The figure consists of two parts:1. **Before the Collision:** - A small car is moving to the right (indicated by the positive direction) with a velocity \(v_{2i}\). - The truck is also moving to the right with a velocity \(v_{1i}\). - The image indicates both vehicles moving towards the right side.2. **After the Collision:** - The small car and truck continue moving to the right. - The truck has a new velocity \(v_f\).**Diagram Summary:**- **Before Collision:** - Car: \(v_{2i} = +22\) m/s - Truck: \(v_{1i} = +14\) m/s- **After Collision:** - Truck: \(v_f = 14.2\) m/s#### Problem:Calculate the change in momentum of the truck measured in kg·m/s.**Solution Steps:**1. **Determine Initial Momentum:** - Initial momentum of the truck: \( p_{1i} = m_1 \cdot v_{1i}\) \( p_{1i} = 8600 \, \text{kg} \times 14 \, \text{m/s}\) \( p_{1i} = 120400 \, \text{kg·m/s} \)2. **Determine Final Momentum:** - Final momentum of the truck: \( p_{1f} = m_1 \cdot v_f\) \( p_{1f} = 8600 \, \text{kg} \times 14.2 \, \text{m/s}\) \( p_{1f} = 122120 \, \text{kg·m/s} \)3. **Calculate Change in Momentum ### Question 4-b, Numerical:A small car of mass 1200 kg is moving with an initial velocity \( v_{2i} = +22 \, \text{m/s} \) and collides with the back of a small truck of 8600 kg moving with an initial velocity \( v_{1i} = +14 \, \text{m/s} \) as shown in the figure. The velocity of the truck after collision is 14.2 m/s.#### Diagram Description:- **Before Collision:** - The diagram shows a small blue car and a large red truck moving to the right (positive direction). The car has an initial velocity \( v_{2i} \) and the truck has an initial velocity \( v_{1i} \).- **After Collision:** - The diagram indicates the same small blue car and large red truck after the collision. The truck now has a new velocity \( v_f = 14.2 \, \text{m/s} \), and the car has an unspecified new velocity \( v_y \).### Problem:Calculate the change in momentum of the car measured in \( \text{kg} \cdot \text{m/s} \).### Solution Steps:1. **Find Initial and Final Momenta:** - Initial momentum of the car: \( p_{2i} = m_2 \cdot v_{2i} = 1200 \, \text{kg} \times 22 \, \text{m/s} = 26400 \, \text{kg} \cdot \text{m/s} \). - Initial momentum of the truck: \( p_{1i} = m_1 \cdot v_{1i} = 8600 \, \text{kg} \times 14 \, \text{m/s} = 120400 \, \text{kg} \cdot \text{m/s} \).2. **Determine Final Velocity of the Car:** - From the conservation of momentum: \[ m_2 v_{2i} + m_1 v_{1i} = m_2 v_{2f} + m_1 v_{1f} \] \[ 26400 + 120400 = 1200 v_{2f} + 8600 \times

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A small car of mass 1200 Kg is moving with initial velocity v2i = + 22 m/s collides the back of a small truck of 8600 kg moving with initial velocity v₁ =+ 14 m/s as shown in the figure. The velocity of the truck after collision is 14.2 m/s. Before After What is the change in momentum of the truck measured in kgm/s?

A small car of mass 1200 Kg is moving with initial velocity v2i = + 22 m/s collides the back of a small truck of 8600 kg moving with initial velocity v₁ =+ 14 m/s as shown in the figure. The velocity of the truck after collision is 14.2 m/s. Before After What is the change in momentum of the truck measured in kgm/s?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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