A radioactive nucleus at rest decays into a second nucleus, anelectron, and a neutrino. The electron and neutrino are emittedat right angles and have momenta ofPe=9.67x10-23 kg. m/s and p = 5.99×10-23 kg. m/s.respectively. (Figure 1)FigurePnucnuc+y0OnucPyPe1 of 1+XPart ADetermine the magnitude of the momentum of the second (recoiling) nucleus.Express your answer to three significant figures and include the appropriate units.Pnuc=SubmitPart BOnuc =SubmitμA 4Provide FeedbackValueRequest AnswerDetermine the angle between the momentum of the electron and the momentum of the second (recExpress your answer using three significant figures.[VE| ΑΣΦ 1→ CRequest AnswerUnits1 ??

We have a nucleus. It is at rest initially. It decays into 3 particles each moving with some momentum. Since there is no external driving agency, the total momentum of the system remains conserved. We then find the x and y component of the momentum of 2nd nucleus. We then find its magnitude. We then find the angle made with electron.Initially the parent nucleus is at rest. Hence initial momentum is pi=0 Momentum of electron pe=9.67×10-23 kgm/s Momentum of neutrino pν=5.99×10-23 kgm/s Let px,py be magnitude of x and y component of momentum of 2nd nucleus. Applying conservation of momentum along x axis, px=pe=9.67×10-23 kgm/s Applying conservation of momentum along y axis, py=pν=5.99×10-23 kgm/s Hence the magnitude of momentum of 2nd nucleus is pnuc=px2+py2pnuc=9.672+5.992×10-23pnuc=11.38×10-23 kgm/s Hence the magnitude of momentum of 2nd nucleus is 11.38×10-23 kgm/s.The angle made of 2nd nucleus with +y axis is given as θ=tan-1pxpyθ=tan-19.675.99θ=tan-11.614θ=58.22o Hence the angle made with electron or the +x axis is θnuc=90+θθnuc=90+58.22θnuc=148.22o Hence the angle made with electron is 148.22o.

Answered: A radioactive nucleus at rest decays…