Nuclear Fusion ReactionIn a human-scale model of a nuclear fusion reaction, two"deuterons" smash together head-on. Each has a mass of2.0147kg and is moving at speed vd.The result is a "Helium-3 nucleus" (mass 3.0160kg) and a separate"neutron" (mass 1.0090kg). Amazingly, this reaction produces apositive Wnc of 3.96 × 10 14 J -- by converting mass into kineticenergy as predicted by Einstein's E mc²=The "neutron" moves with a speed of un after the reaction.E4☑Vd1.57×107 m(no answer)Correct Answer: 3.64SUn×107 mS++D D3НеN.ProtonNeutronhttp://fusion.srubar.net Solution:Conservation of momentum:mava + ma(-va) = Mn Vn + MH (-VH)Solve for VH:VH=MnΜΗUn (Eqn. 1)Conservation of energy (with positive Wnc):2 (mav²) + Wne = ½ m² v²/₁₂ + ½ mн V²/псPlug in for VH from (Eqn. 1):2 (mav²) + Wnc = m₁v² + ½ mClean up:псmav²/2 + Wnc = 1 / (mn +m²ΜΗບPlug in masses of "particles" and Wnc:Mn UnΜΗ2)²(2.0147kg) + (3.96 × 10 14 J) = (.6733kg)v

Answered: Image /qna-images/answer/ce43d372-4134-45fc-888c-52df6754537c.jpg

Nuclear Fusion Reaction In a human-scale model of a nuclear fusion reaction, two "deuterons" smash together head-on. Each has a mass of 2.0147kg and is moving at speed va- The result is a "Helium-3 nucleus" (mass 3.0160kg) and a separate "neutron" (mass 1.0090kg). Amazingly, this reaction produces a positive Wne of 3.96 × 1014 J -- by converting mass into kinetic energy as predicted by Einstein's E = mc². The "neutron" moves with a speed of v₂ after the reaction. E + + D D ³He N. Proton Neutron http://fusion.srubar.net 4 Vd 1.57×107 m (no answer) Correct Answer: 3.64 Un x10m S

Nuclear Fusion Reaction In a human-scale model of a nuclear fusion reaction, two "deuterons" smash together head-on. Each has a mass of 2.0147kg and is moving at speed va- The result is a "Helium-3 nucleus" (mass 3.0160kg) and a separate "neutron" (mass 1.0090kg). Amazingly, this reaction produces a positive Wne of 3.96 × 1014 J -- by converting mass into kinetic energy as predicted by Einstein's E = mc². The "neutron" moves with a speed of v₂ after the reaction. E + + D D ³He N. Proton Neutron http://fusion.srubar.net 4 Vd 1.57×107 m (no answer) Correct Answer: 3.64 Un x10m S

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Relativistic Energy and Momentum

According to classical physics, time flow is the same for every observer. But according to einstein's theory, time flow is different for different observers. The idea that time flow is not the same for all may sound strange because we may not experience this effect in everyday life. This effect is only observed when an object moves with some velocity comparable to the velocity of light. This velocity is termed relativistic velocity.

Question

Nuclear Fusion Reaction
In a human-scale model of a nuclear fusion reaction, two
"deuterons" smash together head-on. Each has a mass of
2.0147kg and is moving at speed vd.
The result is a "Helium-3 nucleus" (mass 3.0160kg) and a separate
"neutron" (mass 1.0090kg). Amazingly, this reaction produces a
positive Wnc of 3.96 × 10 14 J -- by converting mass into kinetic
energy as predicted by Einstein's E mc²
=
The "neutron" moves with a speed of un after the reaction.
E
4
☑
Vd
1.57×107 m
(no answer)
Correct Answer: 3.64
S
Un
×107 m
S
+
+
D D
3Не
N.
Proton
Neutron
http://fusion.srubar.net

Solution:
Conservation of momentum:
mava + ma(-va) = Mn Vn + MH (-VH)
Solve for VH:
VH
=
Mn
ΜΗ
Un (Eqn. 1)
Conservation of energy (with positive Wnc):
2 (mav²) + Wne = ½ m² v²/₁₂ + ½ mн V²/
пс
Plug in for VH from (Eqn. 1):
2 (mav²) + Wnc = m₁v² + ½ m
Clean up:
пс
mav²/2 + Wnc = 1 / (mn +
m²
ΜΗ
ບ
Plug in masses of "particles" and Wnc:
Mn Un
ΜΗ
2)²
(2.0147kg) + (3.96 × 10 14 J) = (.6733kg)v

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