Nuclear Fusion ReactionIn a human-scale model of a nuclear fusion reaction, two"deuterons" smash together head-on. Each has a mass of2.0147kg and is moving at speed vd.The result is a "Helium-3 nucleus" (mass 3.0160kg) and a separate"neutron" (mass 1.0090kg). Amazingly, this reaction produces apositive Wnc of 3.96 × 10 14 J -- by converting mass into kineticenergy as predicted by Einstein's E mc²=The "neutron" moves with a speed of un after the reaction.E4☑Vd1.57×107 m(no answer)Correct Answer: 3.64SUn×107 mS++D D3НеN.ProtonNeutronhttp://fusion.srubar.net Solution:Conservation of momentum:mava + ma(-va) = Mn Vn + MH (-VH)Solve for VH:VH=MnΜΗUn (Eqn. 1)Conservation of energy (with positive Wnc):2 (mav²) + Wne = ½ m² v²/₁₂ + ½ mн V²/псPlug in for VH from (Eqn. 1):2 (mav²) + Wnc = m₁v² + ½ mClean up:псmav²/2 + Wnc = 1 / (mn +m²ΜΗບPlug in masses of "particles" and Wnc:Mn UnΜΗ2)²(2.0147kg) + (3.96 × 10 14 J) = (.6733kg)v

Answered: Image /qna-images/answer/ce43d372-4134-45fc-888c-52df6754537c.jpg

Nuclear Fusion Reaction In a human-scale model of a nuclear fusion reaction, two "deuterons" smash together head-on. Each has a mass of 2.0147kg and is moving at speed va- The result is a "Helium-3 nucleus" (mass 3.0160kg) and a separate "neutron" (mass 1.0090kg). Amazingly, this reaction produces a positive Wne of 3.96 × 1014 J -- by converting mass into kinetic energy as predicted by Einstein's E = mc². The "neutron" moves with a speed of v₂ after the reaction. E + + D D ³He N. Proton Neutron http://fusion.srubar.net 4 Vd 1.57×107 m (no answer) Correct Answer: 3.64 Un x10m S

Nuclear Fusion Reaction In a human-scale model of a nuclear fusion reaction, two "deuterons" smash together head-on. Each has a mass of 2.0147kg and is moving at speed va- The result is a "Helium-3 nucleus" (mass 3.0160kg) and a separate "neutron" (mass 1.0090kg). Amazingly, this reaction produces a positive Wne of 3.96 × 1014 J -- by converting mass into kinetic energy as predicted by Einstein's E = mc². The "neutron" moves with a speed of v₂ after the reaction. E + + D D ³He N. Proton Neutron http://fusion.srubar.net 4 Vd 1.57×107 m (no answer) Correct Answer: 3.64 Un x10m S

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

4. An electron moving at a speed of v₁= 0.960c in the positive x direction collides with another electron at rest. After the collision, one electron is observed to move with a speed of V₁f = 0.956c at an angle of 0₁ = 9.7° with the x axis. (a) Use conservation of momentum to find the velocity (magnitude and direction) of the second electron. (b) Based only on the original data given in the problem, use conservation of energy to find the speed of the second electron.
A subatomic particle A decays into two identical particles B, A=B + B particles. The two B are observed to have exactly equal and opposite momenta of magnitude P.i) What can be deduced about the velocity of A just before the decay? ii) Derive an expression for the mass mOA, of A in terms of mOB and PB.
Bryce, a mouse lover, keeps his four pet mice in a roomy cage, where they spend much of their spare time, when they're not sleeping or eating, joyfully scampering about on the cage's floor. Bryce tracks his mice's health diligently and just now recorded their masses as 0.0133 kg, 0.0223 kg, 0.0245 kg, and 0.0227 kg. At this very instant, the x- and y-components of the mice's velocities are, respectively, (0.637 m/s, –0.173 m/s), (–0.595 m/s, –0.435 m/s), (0.917 m/s, 0.933 m/s), and (-0.725 m/s, 0.787 m/s). Calculate the x- and y-components of Bryce's mice's total momentum, px and py. Px = kg-m/s Py = kg-m/s & TOOLS x10
A moving radioactive particle of mass 5m and kinetic energy T disintegrates into two particles. One of the final particles has mass m and is at rest while the other final particle is massless and is in the forward direction as shown in the figure. What is the threshold/minimum kinetic energy T for this process to occur?
A particle of mass m is moving with speed 2v and collides with a mass 2m moving with speed v in the same direction. After collision, the first mass is stopped completely while the second one splits into two particles each of mass m, which move at angle 45° with respect to the original direction. The speed of each of the moving particle will be (a) √2 v (d) 2√√2 v (b) V √2 V (Ⓒ) (2√2)
Some particles are created via collisions. For instance, pions are created via collisions with high energy protons and carbon, which releases neutrons and pions (which they themself, decay into muons). Suppose two particles with momenta of pi = (2, -1,0,0) kg and p2 = (4,1, 1,0) kg collide. Three particles are created as a result from this collision, two of which have momenta of P3 = (1,0.5, 0, 0) kg and p4 = (1, -1,0,0) kg, determine the four momentum, energy, rest mass and three velocity of the third daughter particle. %3D
Based on a grade 11 physics student, answer the following question:The rebels are fighting the imperials on the icy planet Hoth. Han Solo didn’t dress for the weather (this ain’t Tattooine bud!), and is frozen solid (1234 kg of ice, at -123˚C ). Fortunately for Han, an AT-AT walker shoots its blasters and misses its target but hits Han which vaporizes the ice and brings him to a piping 102˚C. How much heat was added to Han Solo to turn him from a frozen chunk into a ‘Luke-warm’ rebel?
tion 4 of 9 Two particles approach each other with equal and opposite speed, v. The mass of one particle is m, and the mass of the other particle is nm, where n is just a unitless number. Snapshots of the system before, during, and after the elastic collision are shown. Before Collision Aftér m nm m nm Vn.final nm,final After the collision, the first particle moves in the exact opposite direction with speed 1.30v, and the speed of the second particle, Unm,final , is unknown. What is the value of n? n =
A particle of mass m moves with a momentum of magnitude p. Show that the kinetic energy of the particle KE = p2/2m
An unstable particle at rest breaks up into two fragments of unequal mass. The mass of the lighter fragment is equal to 2.60 x 10° -28 kg and that of the heavier fragment is 1.66 × 10° -27 kg. If the lighter fragment has a speed of 0.893c after the breakup, what is the speed of the heavier fragment?
In a proton linear accelerator, protons are accelerated to have a kinetic energy of 520 Me. What is the speed of these protons? (The rest mass of a proton is 1.67 × 10-27 kg.)
An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass mA travels to the left with a speed of vA. Piece B with mass mB travels to the right with speed vB. Show the velocity of piece B in terms of mA, mB and VA. Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: pBf + pAf = 0 Substituting the expression for momentum results to mBv + mAv = 0 Deriving the expression for the velocity of piece B results to