### Problem Statement:A proton with a mass of \(1.672 \times 10^{-27}\) kg is traveling at a velocity of \(5.0 \times 10^6\) m/s. Calculate the momentum of the proton in Newton-seconds (N·s).**Note:** Your answer should be expressed in the highest power possible.### Calculation:To find the momentum (p) of the proton, we use the formula:\[ p = mv \]Where:- \( m \) is the mass of the proton (\(1.672 \times 10^{-27}\) kg)- \( v \) is the velocity of the proton (\(5.0 \times 10^6\) m/s)Substitute the values into the formula:\[ p = (1.672 \times 10^{-27}\ \text{kg}) \times (5.0 \times 10^6\ \text{m/s}) \]### Step-by-step Calculation:1. Multiply the constants: \[ p = 1.672 \times 5.0 = 8.36 \]2. Multiply the powers of 10: \[ 10^{-27} \times 10^{6} = 10^{-21} \] So: \[ p = 8.36 \times 10^{-21} \ \text{kg·m/s} \]Since the SI unit for momentum is Newton-second (N·s), the final answer is already in the correct unit.### Final Answer:The momentum of the proton is \( 8.36 \times 10^{-21} \ \text{N·s} \).

Given data: Mass of proton (m) = 1.672×10-27 kg Velocity (v) = 5.0×106 m/s

Answered: A 1.672*10^-27 kg proton is traveling…

Science

Physics

A 1.672*10^-27 kg proton is traveling at (5.0x10^6) m/s. How many N.s of momentum does it have?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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