Part 4: Peppered Moth Allele and Gene Frequencies The dark allele in peppered moths is dominant (B= p). Light moths are homozygous recessive (bb= q²). Use the data from Table 1 in Lab 1 to calculate the allele and genotype frequencies for peppered moths in year 1 and year 10. 64 Year 1 data: 556 dark moths q² = frequency of bb (light) = ;q= 0.946 frequency of the dominant allele B is p = 1 - q; p = 1 - 0.946 Calculate genotypic makeup of the population. [0.054 _(p) + 0.946_(q)]²= 1; 0.232 _(p²) +_ Genotypic frequencies are: _light moths, 0.896 0.102 0.054 (2pq) + 0.896_(q²) = 1] p² = frequency of BB (dark) 2pq = frequency of Aa (dark)_ q² = frequency of aa(light)
Part 4: Peppered Moth Allele and Gene Frequencies The dark allele in peppered moths is dominant (B= p). Light moths are homozygous recessive (bb= q²). Use the data from Table 1 in Lab 1 to calculate the allele and genotype frequencies for peppered moths in year 1 and year 10. 64 Year 1 data: 556 dark moths q² = frequency of bb (light) = ;q= 0.946 frequency of the dominant allele B is p = 1 - q; p = 1 - 0.946 Calculate genotypic makeup of the population. [0.054 _(p) + 0.946_(q)]²= 1; 0.232 _(p²) +_ Genotypic frequencies are: _light moths, 0.896 0.102 0.054 (2pq) + 0.896_(q²) = 1] p² = frequency of BB (dark) 2pq = frequency of Aa (dark)_ q² = frequency of aa(light)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Answer/calculate the missing parts in the image attached
![Part 4: Peppered Moth Allele and Gene Frequencies
The dark allele in peppered moths is dominant (B= p). Light moths are
homozygous recessive (bb= q²). Use the data from Table 1 in Lab 1 to calculate
the allele and genotype frequencies for peppered moths in year 1 and year 10.
Year 1 data: 556
64
q² = frequency of bb (light) =
_;q=
frequency of the dominant allele B is p = 1 -q; p = 1
Calculate genotypic makeup of the population.
[0.054 (p) + 0.946_(q)]²= 1; 0.232 _(p²) +
Genotypic frequencies are:
_light moths,__
0.896
dark moths
0.946
0.946
0.054
0.102 (2pq) + 0.896_(q²) = 1]
p² = frequency of BB (dark)
2pq = frequency of Aa (dark)_
q² = frequency of aa(light)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9abc94e7-87c4-48d6-80ee-9f462ec0db2c%2Fcbd6d452-473a-4f1e-86f8-c40d51120c6e%2Fnssl8i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Part 4: Peppered Moth Allele and Gene Frequencies
The dark allele in peppered moths is dominant (B= p). Light moths are
homozygous recessive (bb= q²). Use the data from Table 1 in Lab 1 to calculate
the allele and genotype frequencies for peppered moths in year 1 and year 10.
Year 1 data: 556
64
q² = frequency of bb (light) =
_;q=
frequency of the dominant allele B is p = 1 -q; p = 1
Calculate genotypic makeup of the population.
[0.054 (p) + 0.946_(q)]²= 1; 0.232 _(p²) +
Genotypic frequencies are:
_light moths,__
0.896
dark moths
0.946
0.946
0.054
0.102 (2pq) + 0.896_(q²) = 1]
p² = frequency of BB (dark)
2pq = frequency of Aa (dark)_
q² = frequency of aa(light)
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