Part 3. Predict the SN2/Radical Product. Predict the major organic product for each of the following reactions. Be sure to show stereochemistry when appropriate. H3C H H3CH₂C NC -1 NaOH NaOCH3

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Please show every step in reaction it's a Clorniation or Bromnation and how it reacts with with using arrows and step by step on how it works, I'd love to learn this but it's super hard for me.

**Part 3: Predict the SN2/Radical Product**

**Instructions:**
Predict the major organic product for each of the following reactions. Be sure to show stereochemistry when appropriate.

---

**Reaction 1:**

- **Reactant:** 
  - A molecule with an iodine (I) substituent attached to a carbon. This carbon is secondary, bonded to a hydrogen (H) and two alkyl groups: a methyl (CH₃) and an ethyl (CH₂CH₃) group. The configuration is shown with a wedge for the hydrogen, indicating stereochemistry.

- **Reagent:** 
  - Sodium hydroxide (NaOH)

- **Reaction Type:** 
  - Likely an SN2 reaction due to the presence of a strong nucleophile (OH⁻).

---

**Reaction 2:**

- **Reactant:** 
  - A cyclic molecule (five-membered ring) with a cyano (CN) group on one carbon and an iodine (I) substituent on an adjacent carbon. The iodine is depicted with a wedge.

- **Reagent:** 
  - Sodium methoxide (NaOCH₃)

- **Reaction Type:** 
  - Likely an SN2 reaction due to the presence of a strong nucleophile (OCH₃⁻).

---

**Key Points:**

- SN2 reactions typically involve backside attacks, resulting in inversion of configuration at the reaction center.
- Consider stereochemistry by using wedges and dashes to indicate the three-dimensional arrangement of atoms.
- Predict the products by substituting the leaving group (Iodine, I) with the nucleophile provided by the reagent.
Transcribed Image Text:**Part 3: Predict the SN2/Radical Product** **Instructions:** Predict the major organic product for each of the following reactions. Be sure to show stereochemistry when appropriate. --- **Reaction 1:** - **Reactant:** - A molecule with an iodine (I) substituent attached to a carbon. This carbon is secondary, bonded to a hydrogen (H) and two alkyl groups: a methyl (CH₃) and an ethyl (CH₂CH₃) group. The configuration is shown with a wedge for the hydrogen, indicating stereochemistry. - **Reagent:** - Sodium hydroxide (NaOH) - **Reaction Type:** - Likely an SN2 reaction due to the presence of a strong nucleophile (OH⁻). --- **Reaction 2:** - **Reactant:** - A cyclic molecule (five-membered ring) with a cyano (CN) group on one carbon and an iodine (I) substituent on an adjacent carbon. The iodine is depicted with a wedge. - **Reagent:** - Sodium methoxide (NaOCH₃) - **Reaction Type:** - Likely an SN2 reaction due to the presence of a strong nucleophile (OCH₃⁻). --- **Key Points:** - SN2 reactions typically involve backside attacks, resulting in inversion of configuration at the reaction center. - Consider stereochemistry by using wedges and dashes to indicate the three-dimensional arrangement of atoms. - Predict the products by substituting the leaving group (Iodine, I) with the nucleophile provided by the reagent.
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