Please solve and explain? **Exercise 15**: Carefully draw the mechanism of the following reaction using arrows to show the movement of electrons.### Reaction Details:- **Reactants**: Benzene ring (C₆H₅) and Bromine (Br₂)- **Catalyst**: Iron(III) bromide (FeBr₃)- **Product**: Bromobenzene (C₆H₅Br)### Reaction Description:In this reaction, benzene undergoes electrophilic aromatic substitution with bromine in the presence of FeBr₃, a catalyst. The key steps involved in this mechanism include the generation of a bromonium ion, attack of the benzene π-electrons on the bromonium ion, and the reformation of the aromatic system.1. **Formation of the Electrophile**: - Br₂ reacts with FeBr₃ to form Br⁺ and FeBr₄⁻.2. **Electrophilic Attack**: - The Br⁺ electrophile is attacked by the π-electrons of the benzene ring, forming a carbocation intermediate.3. **Deprotonation**: - The hydrogen adjacent to the carbocation is removed by FeBr₄⁻, restoring aromaticity to the ring and releasing HBr.Overall, this reaction yields bromobenzene, a product wherein one hydrogen of the benzene ring is substituted with a bromine atom.

The given reaction is an example of Electrophilic Bromination of Benzene. This reaction occurs in…

Answered: Carefully draw the mechanism of the…

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Carefully draw the mechanism of the following reaction using arrows to show the movement of electrons: Br Br2 FeBr3

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Please solve and explain?

**Exercise 15**: Carefully draw the mechanism of the following reaction using arrows to show the movement of electrons.

### Reaction Details:
- **Reactants**: Benzene ring (C₆H₅) and Bromine (Br₂)
- **Catalyst**: Iron(III) bromide (FeBr₃)
- **Product**: Bromobenzene (C₆H₅Br)

### Reaction Description:
In this reaction, benzene undergoes electrophilic aromatic substitution with bromine in the presence of FeBr₃, a catalyst. The key steps involved in this mechanism include the generation of a bromonium ion, attack of the benzene π-electrons on the bromonium ion, and the reformation of the aromatic system.

1. **Formation of the Electrophile**:
- Br₂ reacts with FeBr₃ to form Br⁺ and FeBr₄⁻.

2. **Electrophilic Attack**:
- The Br⁺ electrophile is attacked by the π-electrons of the benzene ring, forming a carbocation intermediate.

3. **Deprotonation**:
- The hydrogen adjacent to the carbocation is removed by FeBr₄⁻, restoring aromaticity to the ring and releasing HBr.

Overall, this reaction yields bromobenzene, a product wherein one hydrogen of the benzene ring is substituted with a bromine atom.

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