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Chemistry
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Chapter1: Chemical Foundations
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**Problem Statement:**

Prove that 

\[
\left( \frac{\partial}{\partial T} \left( \frac{G}{T} \right) \right)_P = -\frac{H}{T^2}.
\]

**Explanation:**

This expression is a thermodynamic relation involving partial derivatives. It is commonly used in the context of Gibbs free energy (\(G\)), temperature (\(T\)), and enthalpy (\(H\)).

**Details:**

- The left-hand side of the equation, \(\left( \frac{\partial}{\partial T} \left( \frac{G}{T} \right) \right)_P\), represents the partial derivative of \( \frac{G}{T} \) with respect to temperature \(T\), while holding pressure \(P\) constant.
- The right-hand side, \(-\frac{H}{T^2}\), indicates that this derivative is equal to the negative of the enthalpy divided by the square of the temperature.

This relation is essential for understanding the temperature dependence of Gibbs free energy in various thermodynamic processes.
Transcribed Image Text:**Problem Statement:** Prove that \[ \left( \frac{\partial}{\partial T} \left( \frac{G}{T} \right) \right)_P = -\frac{H}{T^2}. \] **Explanation:** This expression is a thermodynamic relation involving partial derivatives. It is commonly used in the context of Gibbs free energy (\(G\)), temperature (\(T\)), and enthalpy (\(H\)). **Details:** - The left-hand side of the equation, \(\left( \frac{\partial}{\partial T} \left( \frac{G}{T} \right) \right)_P\), represents the partial derivative of \( \frac{G}{T} \) with respect to temperature \(T\), while holding pressure \(P\) constant. - The right-hand side, \(-\frac{H}{T^2}\), indicates that this derivative is equal to the negative of the enthalpy divided by the square of the temperature. This relation is essential for understanding the temperature dependence of Gibbs free energy in various thermodynamic processes.
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