-Know the reaction mechanism for all chemistry in this lab (forming the acid chloride, then the amide/anilide/toluidide derivative). -Understand how choosing a derivative and measuring its melting point allows us to narrow down the identity of an unknown carboxylic acid. How do you know which derivative is the best one to make? -Be able to calculate percent and theoretical yields.

Please only answer if you are sure of the answer The choices are - Only Hydroxide - Only bicarbonate -Hydroxide or Bicarbonate -Neither hydroxide nor bicarbonate

D. OXIDATION OF ALCOHOLS1. Place 1 mL of each of the following alcohols in separate clean test tubes: ethanol,benzyl alcohol and ethylene glycol.2. To each alcohol sample, add 2 mL of acidified potassium dichromate solution.Mix by shaking gently and observe any changes. Warm gently if necessary to startthe reaction.Record results in the table below.Alcohol                                               Color changes observed Ethyl AlcoholBenzyl AlcoholGlycerol Equations for the oxidation of each alcohol:a. _________________________________________________________________b. _________________________________________________________________c. _________________________________________________________________E. FORMATION OF ESTERS1. To 2 mL of ethyl alcohol, add 1 mL of glacial acetic acid and 2 drops ofconcentrated sulfuric acid (CAUTION). Warm gently, then pour into a beakercontaining 20 mL of ice water previously made alkaline with sodium carbonatesolution. Stir well and note the…

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ciple Attempts Not allowed. This test can only be taken once. ce Completion Once started, this test must be completed in one sitting. Do not leave the test before clicking Save and Submit This test does not allow backtracking. Changes to the answer after submission are prohibited. emaining Time: 52 minutes, 44 seconds. Question Completion Status: A Moving to the next question prevents changes to this answer. Question 2 Reaction of arenediazonium salts with aryl benzene give.... o Aryl halied Benzonitrile Phenole Azo dayes A Moving to the next question prevents changes to this answer. P Type here to search 1HUAWE F1 F2 F3 F4 F5 F6 F7 %23 24 % & 2 5 6. 7 8. Q W E T Y. us A H. 1S C, Z C VI B U DI

Considering the procedure, time, and volatility of solvents; which paragraph represents a good starting point for the next lab? The one that starts with "the stilbenes" The one that starts with "Add an additional" The one that starts with "Prolonged exposure" The one that starts with "Triturate the residue" The one that starts with "The benzaldehyde" This one that starts with "An interesting synthetic" O The one that starts with "Prepare a suspension" O The one that starts with "This conversion" The one that starts with "Concentrated solutions"

Preamble: A student chemist in an attempt to synthesise compound B from the aromatic aldehyde.  24. What is the reaction name for the chemical transformation of A to BA. reductive aminationB. catalytic reductionC. carbonyl dehydrationD. Hofmann eliminationE. Aldehyde rearrangement

I need this explained by using orbitals not just the mechanism....PLEASE show orbitals or allow someone else to answer the question.

Can you help me correcting  question 1 with this notes? Notes:Say something about rates here. Did HCl therefore react more quickly than the sulfuric acid, or does the difference in pKas at such a low value matter? , why would a big difference in the two acids' pKas lead to a "minimal" rate difference? Please restate this sentence so that it makes logical sense!  1. Hydrochloric, nitric and sulfuric acids are considered to be strong acids; that is, they dissociate completely into ions, such as H+. Were there any differences in reaction rates with magnesium between these three acids? If so, what distinguishing feature of the acids might explain the differences? It is because the lower the pKa value the higher its Ka value. This means that HCl will dissociate into protons and chloride ions more easily than sulfuric acid, and sulfuric acid will dissociate faster than nitric acid.