Part 2: Recursive Fractals Examine this pattern of asterisks and blanks, and write a recursive function called pattern() that can generate patterns such as this: pattern(3, 2); pattern(5, 1); pattern(7, 0); With recursive thinking, the function needs only about 10 lines of code (including two recursive calls). Your function prototype should look like this: I/ Description: II The longest line of the pattern has n stars beginning in column col of the output. I/ Precondition: n is an positive odd number. I/ Postcondition: A pattern based on the above example has been printed. void pattern (int n, int col); No error handling needed for this part. Assume that user will provide you a positive odd int as n, and a non-negative int as col. Hint: Think about how the pattern is a fractal. Can you find two smaller versions of the pattern within the large pattern? Here is some code that may be helpful within your function: // A loop to print exactly col columns for (int i = 0; i < col; i++) cout <« " "; // A loop to print n asterisks, each one followed by a space: for (int i = 0; i < n; i++) cout « "* ";

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Part 2: Recursive Fractals
Examine this pattern of asterisks and blanks, and write a recursive function called pattern() that can
generate patterns such as this:
pattern(3, 2);
pattern(5, 1);
pattern(7, 0);
With recursive thinking, the function needs only about 10 lines of code (including two recursive calls).
Your function prototype should look like this:
// Description:
I/ The longest line of the pattern has n stars beginning in column col of the output.
// Precondition: n is an positive odd number.
// Postcondition: A pattern based on the above example has been printed.
void pattern (int n, int col);
No error handling needed for this part. Assume that user will provide you a positive odd int as n, and a
non-negative int as col.
Hint: Think about how the pattern is a fractal. Can you find two smaller versions of the pattern within the
large pattern? Here is some code that may be helpful within your function:
// A loop to print exactly col columns
for (int i = 0; i < col; i++) cout <« "
";
// A loop to print n asterisks, each one followed by a space:
for (int i = 0; i < n; i++) cout « "* ";
Transcribed Image Text:Part 2: Recursive Fractals Examine this pattern of asterisks and blanks, and write a recursive function called pattern() that can generate patterns such as this: pattern(3, 2); pattern(5, 1); pattern(7, 0); With recursive thinking, the function needs only about 10 lines of code (including two recursive calls). Your function prototype should look like this: // Description: I/ The longest line of the pattern has n stars beginning in column col of the output. // Precondition: n is an positive odd number. // Postcondition: A pattern based on the above example has been printed. void pattern (int n, int col); No error handling needed for this part. Assume that user will provide you a positive odd int as n, and a non-negative int as col. Hint: Think about how the pattern is a fractal. Can you find two smaller versions of the pattern within the large pattern? Here is some code that may be helpful within your function: // A loop to print exactly col columns for (int i = 0; i < col; i++) cout <« " "; // A loop to print n asterisks, each one followed by a space: for (int i = 0; i < n; i++) cout « "* ";
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