Im sorry but i dont understand the following:"Hi and thanks for your question! Unfortunately, per our honor code, graded questions cannot be answered. We've credited a question back to your account. Apologies for the inconvenience."I just asked what where did the hydrogen in green go. It is a worked out practice problem. They already give the answer and I dont understand a step. Part [2] Addition of the nucleophile and loss of the leaving groupн.:0::ö::ö:н.:0:R'N:R:N:R.nucleophilicattackH-Nloss of theleaving groupнНнR'R'R'NH2amide3 Nucleophilic attack of the amine on the activated carboxy group forms a tetrahedral intermediate.4 - 5 Proton transfer and elimination of dicyclohexylurea as the leaving group form the amide.The reaction of an acid and an amine with DCC is often used in the laboratory to form the amide bond in peptides, as is Page 903discussed in Chapter 26 (2Problem 22.19What product is formed when acetic acid is treated with each reagent: (a) CH,NH,; (b) CH-NH,, then

Since the N is having a + charge on it. So it will lose try to take the electrons from the N-H bond.…

Answered: Part [2] Addition of the nucleophile…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Im sorry but i dont understand the following:

"Hi and thanks for your question! Unfortunately, per our honor code, graded questions cannot be answered. We've credited a question back to your account. Apologies for the inconvenience."

I just asked what where did the hydrogen in green go. It is a worked out practice problem. They already give the answer and I dont understand a step.

Part [2] Addition of the nucleophile and loss of the leaving group
н.
:0:
:ö:
:ö:
н.
:0:
R'
N:
R:
N:
R.
nucleophilic
attack
H-N
loss of the
leaving group
н
Н
н
R'
R'
R'NH2
amide
3 Nucleophilic attack of the amine on the activated carboxy group forms a tetrahedral intermediate.
4 - 5 Proton transfer and elimination of dicyclohexylurea as the leaving group form the amide.
The reaction of an acid and an amine with DCC is often used in the laboratory to form the amide bond in peptides, as is Page 903
discussed in Chapter 26 (2
Problem 22.19
What product is formed when acetic acid is treated with each reagent: (a) CH,NH,; (b) CH-NH,, then

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