Part 1) Please draw and label a free body diagram of Harzan at the bottom of the swing.  Part 2) What forces act as the radial force in the circular motion?  Part 3) Is this uniform circular motion? Explain

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Chapter1: Units, Trigonometry. And Vectors
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Please refer to the picture with the formulas and constants that need to be used in this problem.

Harzan wants to swing from one bank of the river to the other using an overhaning vine. As he swings, he traces out an arc of a circle. 

Part 1) Please draw and label a free body diagram of Harzan at the bottom of the swing. 

Part 2) What forces act as the radial force in the circular motion? 

Part 3) Is this uniform circular motion? Explain 

Part 4) The vine is 6.2 m long, and Harzan's mass is 85 kg. At the bottom of his swing, he is travelling at 4.3 m/s. What is the magnitide of the radial acceleration that Harzan experiences? 

Part 5) How much tension must the vine support in order to safely transport Harzan over the river? 

Please answer all parts 

Formulas
daug = AV > Vp = √₂ + aaug At
->
At
Vaug = 1/2 (V₂ + √₂)
Vaug = AX X₁ = X₁ + Vaug At
At
X²₁ = X₁ + √₂ At + ½ åst ²
2
2
V² = V₁² + 2aAx
F = ma
F₁ = M₁₂₁ FN
AR = V²
F₁B = - F₁A
BA
F₁ ≤ M₂ FN
FG = G m₁m₂
r²
f ===
T
O
Constants
C≈ 3 x 10³ m/s
9 = 9.8 m/s²
G = 6.7 x 10" Nm² / Kg ²
Units
t = 5
x = m
✓ = m/s
a = m/s²
m = 19
F² = N
T= 3
f = H₂ = 1/s
Geometry
A = lw
A = 1/2 bh
A = πTr ²
C=2 TTC
Tuncertainty Propagation
C=dA →> 0c = |d0A
C = Aª² >> °C = |d² A
Ad
C = A±B20² = 0 ² ² + 0 ²₁₂
ога
C=AB or C => 04
A
न्ह
B
C²
A²
+
B
B²
Transcribed Image Text:Formulas daug = AV > Vp = √₂ + aaug At -> At Vaug = 1/2 (V₂ + √₂) Vaug = AX X₁ = X₁ + Vaug At At X²₁ = X₁ + √₂ At + ½ åst ² 2 2 V² = V₁² + 2aAx F = ma F₁ = M₁₂₁ FN AR = V² F₁B = - F₁A BA F₁ ≤ M₂ FN FG = G m₁m₂ r² f === T O Constants C≈ 3 x 10³ m/s 9 = 9.8 m/s² G = 6.7 x 10" Nm² / Kg ² Units t = 5 x = m ✓ = m/s a = m/s² m = 19 F² = N T= 3 f = H₂ = 1/s Geometry A = lw A = 1/2 bh A = πTr ² C=2 TTC Tuncertainty Propagation C=dA →> 0c = |d0A C = Aª² >> °C = |d² A Ad C = A±B20² = 0 ² ² + 0 ²₁₂ ога C=AB or C => 04 A न्ह B C² A² + B B²
Expert Solution
Step 1

Given, 

A person uses over hanging vine to cross a river.

Mass of the person is m=85 kg

Length of vine used l=6.2 m

At the bottom of swing, velocity of the person is v=4.3 m/s

 

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