The 4.7-lb slider moves along the fixed curved bar with radius r =2.3 ft which lies in a vertical planAt the position shown, where 0 =25°, the slider has a speed of 5.7 ft/sec. Determine the magnitudof the normal force exerted by the fixed rod on the slider. Give your answer in Ib.A

using, Normal-tangential (n-t) coordinate system to solve the problemFrom the free body diagram , balancing the forces in tangential coordinate direction Ft= mat-mgsinθ=m×at-Wsingθ=Wg×at-4.7 sin 25=4.732.2×at we know that 1lbf=32.2 ft-lb s-2at=-13.6 ft s-2Negative sign indicates that the speed of the slider is decreasingSimilarly, Balancing the forces in the normal coordinate direction gives,Fn=mv2rN+mgcosθ=mv2rcan be written asN+W cosθ=Wg×v2rN+4.7 lb cos 25=4.7 lb 32.2 ft-lb/s2×5.7 ft/sec22.3 ftN=2.06-4.25=-2.19 lbAnswer:Force exerted by fixed rod on the slider is 2.19 lb in opposite direction

Answered: The 4.7-lb slider moves along the fixed…

The 4.7-lb slider moves along the fixed curved bar with radius r =2.3 ft which lies in a vertical plan At the position shown, where 0 =25°, the slider has a speed of 5.7 ft/sec. Determine the magnitud of the normal force exerted by the fixed rod on the slider. Give your answer in Ib. A