Part 1 of 2 0.061 mg in 1400. g plankton. Be sure your answer has the correct number of significant figures. Note: Reference the SI prefixes table for additional information. ppm DDT x10 Part 2 of 2 X G 558. ug in 1.6 kg breast milk. Be sure your answer has the correct number of significant figures. Note: Reference the SI prefixes table for additional information. ppm DDT x10

Part 1 of 2 0.061 mg in 1400. g plankton. Be sure your answer has the correct number of significant figures. Note: Reference the SI prefixes table for additional information. ppm DDT x10 Part 2 of 2 X G 558. ug in 1.6 kg breast milk. Be sure your answer has the correct number of significant figures. Note: Reference the SI prefixes table for additional information. ppm DDT x10

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Can someone please help with question?
Read and interpret the following information using the following abstract from a scientific journal article. In 2-3 sentences, summarize what you understand from this research
Li is an incomplete answer. Please choose from one of the anser options provided.
I picked this answer before and it was incorrect
student found a bottle of unknown origin in the basement of an "CAUTION—contains С₁H₁O.” No other A old house. The bottle was labelled information was given, but inside the bottle were some white crystals. The student took the bottle to a chemistry laboratory, where she analyzed the crystals with the help of the laboratory staff. C₁2H₁6O reacted with Br₂ in CCl4 adding one mole of Br, and forming C₁₂H₁OB2₂. When a sample of C₁₂H₂O was reacted with O3 followed by Zn/H₂O, two different samples, J and K, were obtained. Compound J had a molecular formula of C.HgO₂, and its NMR is shown below. Compound K had a molecular formula of C₂H₂O, and it could be oxidized to compound L, with a molecular formula of C₂H₂O₂. The IR spectrum of L showed a very wide, strong band centred around 3000 cm*¹. The NMR spectrum of L showed only two different absorptions: a doublet (6H) at 0.9 ppm and a septet (1H) at 3.6 ppm. There was also a singlet (1H) off the scale at 11.8 ppm. students, deduce possible…
Step 3 of 8 Sum the equations for d[H] and d[Br] and solve for [Br]. (Use the following as necessary: [Br2], [H], [H2], [HBr], k1, k2, k3, k4, and k5.) dt dt [Br] = K5 2k1 [Br.] 2k [Br2] ks Step 4 of 8 Using the equation for I from Step 2, solve for [H]. (Use the following as necessary: [Br], [Br2], [H2], [HBr], k1, k2, k3, k4, and k5.) dt ky[ Br][H,] kg[Br] + k4 [HBr] [H] = k2[Br][H2] k3[Br2] + k4[HBr] Step 5 of 8 Substitute the equation for [Br] from Step 3 into the equation for [H] from Step 4 and simplify. (Use the following as necessary: [Br2], [H2], k1, k2, k3, k4, and k5.) k, k5 [Br.] [H] k3[Br2] + k4[HBr] Submit
This what it just said to me. Incorrect, So what information goes in the boxes in the parentheses
please help with parts e,h,i with explanation as to hoe they are named
A calibration curve was created to determine the quantity of protein in a solution. The calibration curve has the form of a straight line with the equation ?=0.0182?+0.007 where ? is the corrected absorbance of the solution and ? is quantity of protein in the solution in units of micrograms (μg). Determine the quantity of protein in a solution that has an absorbance of 0.305. A blank solution has an absorbance of 0.060. The answer (Quantity of protein) should be in units of (μg)
Thank you. I'm just confused as what is is the reason 122.1 has to be multiplied by (-45543.23)?
2+ d. 4H3O+ (aq) + 2Cl(aq) + MnO₂ (s) ⇒ Mn²+ (aq) + 6H₂O(1) + Cl₂ (9) Oke O Ke = = O Ke = 2+ [Mn²+ ][C1₂] [H3O+] * [CI-1² [Mn²+][H₂O][C1₂] 2+ [H³O+][CI¯]²[MnO₂2] [Mn²+ ] [H₂O1] [C1₂] 2+ [H3O+] * [CI-1²[MnO₂]
is this a Z or E? and why is it.