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Part 1: Given that Z is a standard normal random variable, compute the following probabilities: a) P(Z ≤ 1.64) = b) P(Z > -1.52) = c) P(Z ≤ 1.2)

Part 1: Given that Z is a standard normal random variable, compute the following probabilities: a) P(Z ≤ 1.64) = b) P(Z > -1.52) = c) P(Z ≤ 1.2)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Fill in the blank by using drag and drop one of the following answers (some options will not be used): Part 1: Given that Z is a standard normal random variable, compute the following probabilities: a) P(Z ≤ 1.64) = b) P(Z > -1.52) c) P(Z ≤ 1.2) d) P(Z < ) = 0.0073 Part 2: The Italian National Bank is reviewing its current account service charges and interest payment procedures. The average daily balance is Normally distributed, with a mean of £575 and a standard deviation of £125, according to the bank. The probability of current users having more than £780 in their accounts is The probability of current users having between £600 and £750 in their accounts is -2.44 0.9357 0.9308 0.8849 -0.46 0.9495 0 1587 04129
Transcribed Image Text:Fill in the blank by using drag and drop one of the following answers (some options will not be used): Part 1: Given that Z is a standard normal random variable, compute the following probabilities: a) P(Z ≤ 1.64) = b) P(Z > -1.52) c) P(Z ≤ 1.2) d) P(Z < ) = 0.0073 Part 2: The Italian National Bank is reviewing its current account service charges and interest payment procedures. The average daily balance is Normally distributed, with a mean of £575 and a standard deviation of £125, according to the bank. The probability of current users having more than £780 in their accounts is The probability of current users having between £600 and £750 in their accounts is -2.44 0.9357 0.9308 0.8849 -0.46 0.9495 0 1587 04129
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