P(zszo) = 0.0886 d. P(-zo sz

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Find a value of the standard normal random variable z, call it zo, such that the following probabilities are satisfied.
P(zszo) = 0.0886
d. P(-zo sz<zo) = 0.1718
a.
hts
b. P(zszo) = 0.7213
P(zo szs0) = 0.2730
е.
P(-zo sz<zo) = 0.7278
P(-3<z<zo) = 0.9551
с.
f.
a. Zo
(Round to two decimal places as needed.)
Transcribed Image Text:Find a value of the standard normal random variable z, call it zo, such that the following probabilities are satisfied. P(zszo) = 0.0886 d. P(-zo sz<zo) = 0.1718 a. hts b. P(zszo) = 0.7213 P(zo szs0) = 0.2730 е. P(-zo sz<zo) = 0.7278 P(-3<z<zo) = 0.9551 с. f. a. Zo (Round to two decimal places as needed.)
Expert Solution
Step 1

To find the value of the standard normal variable z0, such that the following probabilities are satisfied:

(a) Pzz0=0.0886

Using Excel Function "=NORM.S.INV(0.0886)", z value corresponding to probability 0.0886 is -1.34943.

Or Using a standard normal table, look up for probability 0.0886 in the entries of the table, 0.0886 lies between 0.09012 and 0.08851, consider the z-score corresponding to the nearest probability which is 0.08851, so it's corresponding z value is -1.35

Statistics homework question answer, step 1, image 1

Therefore, required value of z0 is -1.35

 

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