Listed in the accompanying table are heights (in.) of mothers and their firstdaughters. The data pairs are from a journal kept by Francis Galton. Use thelisted paired sample data, and assume that the samples are simple randomsamples and that the differences have a distribution that is approximately normal.Use a 0.01 significance level to test the claim that there is no difference in heightsbetween mothers and their first daughters.Mother61.0 69.0 60.0 66.0 65.5 64.0 63.5 63.0 68.5 69.0 DDaughter63.5 68.0 62.0 67.0 65.2 69.0 63.5 63.0 66.0 70.0In this example, Ha is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the daughter's heightminus the mother's height. What are the null and alternative hypotheses for the hypothesis test?Ho: Hdin.H1: Hdin.(Type integers or decimals. Do not round.)Identify the test statistic.t= (Round to two decimal places as needed.)Identify the P-value.P-value =(Round to three decimal places as needed.)What is the conclusion based on the hypothesis test?Since the P-value isV the significance level,the null hypothesis. ThereV sufficient evidence to warrant rejection of the claim thatthere is no difference in heights between mothers and their first daughters.

Given Level of significance=0.01

Answered: paired sample data, and assume that the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Please show five steps in hypothesis testing. When the sample size is larger than 30 for both samples, we assume the concerned sampling distribution approximates a normal curve, and we can compute the obtained z score. We also focus on the two-tailed test and the research/alternative hypothesis simply predicts the population means are different.
This question have 4 parts,Please help with all 4 please
Test the indicated claim about the means of two populations. Assume that the two samples are randomly selected, independent, the population standard deviations are not know and not considered equal. Two types of cereal ? are test for their consumption time (in minutes). At the 0.01 significance level, test the claim that the two populations of cereal have equal means. Cereal A Cereal B n1 = 37 n2 = 35 xˉx̄1 = 19.6 min xˉx̄2 = 19.1 min s1 = 1.7 min s2 = 0.6 min What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.)H0: Select an answer p₁ x̄₁ μ₂ p̂₁ x̄₂ μ μ(A) p s₁² p₂ σ₁² μ₁ ? > ≥ ≤ < = ≠ Select an answer μ(B) p₁ p p₂ x̄₂ μ x̄₁ s₁² μ₂ μ₁ p̂₁ σ₁² H1: Select an answer σ₂² μ₂ x̄₁ p̂₂ p₁ μ₁ s₂² x̄₂ μ μ(A) p₂ p ? > = ≠ ≥ ≤ < Select an answer p₁ p μ₂ s₁² μ₁ x̄₁ p̂₁ p₂ μ(B) σ₁² μ x̄₂ Original Claim = Select an answer H₁ H₀ df = Based on the hypotheses, find the following: Test Statistic = (Round to three decimal…
A simple random sample of 85 basketball players is taken from different teams and their mean weight is found to be 230 pounds and the standard deviation of the population is 18 pounds .At the significance level of 0.01 test the claim that the average weight for all basket ball players is 225 pounds.use the traditional method of hypothesis testing
A researcher is interested in studying mean gill beat rates for fish in water with three different levels of calcium. The results of the experiment are stored in below. Set up the null and alternative hypotheses. What is the mean square error? State the F-statistic of the test as well as the p-value of the test. What is the conclusion of the test, in context? Test which two levels of calcium are most likely to find a difference in mean gill rates. State all three pairwise hypothesis tests and the p-values for each test. Calcium GillRate Low 55 Low 63 Low 78 Low 85 Low 65 Low 98 Low 68 Low 84 Low 44 Low 87 Low 48 Low 86 Low 93 Low 64 Low 83 Low 79 Low 85 Low 65 Low 88 Low 47 Low 68 Low 86 Low 57 Low 53 Low 58 Low 47 Low 62 Low 64 Low 50 Low 45 Medium 38 Medium 42 Medium 63 Medium 46 Medium 55 Medium 63 Medium 36 Medium 58 Medium 73 Medium 69 Medium 55 Medium 68 Medium 63 Medium 73 Medium 45…
Because Mike and Ikes are your favorite candy, you decided to apply statistics to them. Assume your bag of Mike and Ikes is a simple random sample. Suppose you have 23 Mike and Ikes. The lengths of Mike and Ikes in your bag are normally distributed with a mean of 1.5 cm and standard deviation of 0.15 cm. Create a 99% confidence interval for the variance of Mike and Ikes lengths.
In a one-way ANOVA, what does Eta-squared mean? 1, it is the squared F-ratio 2. it is the proportion of variability that can be accounted for by the variability between the groups 3. it is the distance between the sample mean and the population mean in terms of standard deviation 4. it is the ratio of the variance betweeen the groups and the variance within the groups
please help me also find the p value and what the conclusion would be. Thank you!
Do men have a higher body temperature than women? Test the indicated claim about the means of two populations. Assume that the two samples are randomly selected, independent, the population standard deviations are not know and not considered equal. The table shows results from a study of body temperatures of men and women. At the 0.05 significance level, test the claim that men have a higher body temperature than women. Men Women n1 = 13 n2 = 16 xˉx̄1 = 97 °F xˉx̄2 = 95.17 °F s1 = 0.26 °F s2 = 0.57 °F What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.)H0: Select an answer x̄₂ μ₁ p p₂ μ₂ μ μ(men) p̂₁ x̄₁ σ₁² p₁ s₁² ? > < ≥ ≠ ≤ = Select an answer p̂₁ p₁ μ μ₁ p x̄₁ μ₂ s₁² x̄₂ μ(women) σ₁² p₂ H1: Select an answer σ₂² μ p̂₂ p₁ p p₂ x̄₁ μ(men) x̄₂ μ₂ μ₁ s₂² ? = ≤ > < ≥ ≠ Select an answer s₁² x̄₁ μ₂ μ p̂₁ x̄₂ σ₁² μ(women) p₁ p p₂ μ₁ Original Claim = Select an answer H₀ H₁ df = Based on the hypotheses, find…
For a one-tailed hypothesis test (upper tail) the p-value is computed to be 0.008. If the test is being conducted at 99% confidence, the null hypothesis could be rejected or not rejected depending on the sample size could be rejected or not rejected depending on the value of the mean of the sample is not rejected is rejected
Pedro was working on a report on Swiss and Austrian psychiatrists. He decided to find a 90 percent confidence interval for the difference in mean age at the time of significant psychiatric discoveries for Swiss versus Austrian psychiatrists. He found the ages at the time of psychological discovery of all the members of both groups and found the 90 percent confidence interval based on a t-distribution using a calculator. The procedure he used is not appropriate in this context because O The sample sizes for the two groups are not equal. O The entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used. O Age at the time of psychological discovery occurs at different intervals in the two countries, so the distribution of ages cannot be the same. O Age at the time of psychological discovery is likely to be skewed rather than bell shaped, so the assumptions for using this confidence interval formula are not…
Find the 98% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample Number Mean Std. Dev. 1 16 38 29 2 29 28 29 Lower Limit Upper Limit

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