Test the indicated claim about the means of two populations. Assume that the two samples areindependent simple random samples selected from normally distributed populations. Do notassume that the population standard deviations are equal. Use the traditional method or P-value method as indicated.A researcher was interested in comparing the resting pulse rates of people who exercise regularlyand of those who do not exercise regularly. Independent simple random samples of 16 peoplewho do not exercise regularly and 12 people who exercise regularly were selected, and theresting pulse rates (in beats per minute) were recorded. The summary statistics are as follows.Do not exercise regularlv yExercise regularlyx1 = 73.0 be ats/min x = 68.4 beats/mins1 = 10.9be ats/min s = S.2 beats/minnį = 16n2 = 12Use a 0.025 significance level to test the claim that the mean resting pulse rate of people who donot exercise regularly is larger than the mean resting pulse rate of people who exercise regularly.Use the traditional method of hypothesis testing. One Right Tail Test-Z table

The objective is to test the claim that the mean resting pulse rate of people who do not exercise…

= random samples selected from normally distributed pulation standard deviations are equal. Use the tradit dicated. terested in comparing the resting pulse rates of people o not exercise regularly. Independent simple random s e regularly and 12 people who exercise regularly were in beats per minute) were recorded. The summary stat Ev Exercise regularly =68.4 be ats/min a x) %3D n s2 = 8.2 beats/min n2 = 12 ance level to test the claim that the mean resting pulse than tho an resting pulse rate of people

= random samples selected from normally distributed pulation standard deviations are equal. Use the tradit dicated. terested in comparing the resting pulse rates of people o not exercise regularly. Independent simple random s e regularly and 12 people who exercise regularly were in beats per minute) were recorded. The summary stat Ev Exercise regularly =68.4 be ats/min a x) %3D n s2 = 8.2 beats/min n2 = 12 ance level to test the claim that the mean resting pulse than tho an resting pulse rate of people

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

I researched the winning time for the 1/4 mile race in the Fayette County Fair. Let's assume that winning times are normally distributed for both men and women. The mean time for men is 43.92s with a standard deviation of 0.38s. The men's fastest time has a z-score of -1.95. What is the time associated with men's z-score? T TTArial 3 (12pt) Click Save and Submit to save and submit. Click Save All Answers to save all answers.
The annual per capita consumption of oranges (in pounds) in the United States can be approximated by a normal distribution. The mean annual per capita consumption of oranges (in pounds) is 19.2 with a standard deviation of 4 pounds. What annual per capita consumption of oranges represents the 5th percentile? What annual per capita consumption of oranges represents the third quartile? • The time spent (in days) waiting for a heart transplant in Ohio and Michigan for patients with A+ blood can be approximated by a normal distribution with a mean waiting time of 127 days and a standard deviation of 23.5 days. What is the minimum time spent waiting for a heart that would place a patient in the top 30% of waiting times? In a certain year, the nationwide SAT verbal score averaged 430 with a standard deviatioh of 96. Assuming a normal distribution and continuous scores over the scale, between what two values would you expect to find the middle 90% of SAT verbal scores in the year noted?…
PEF is a measure of patient's abiltity to expel air from lungs. PEF for children free of asthma is 306. investigator wants to know whether children with chronic bronchitis have restricted PEF. sample of 40 children with chronic bronchitis are studied, their mean PEF is 279, standard deviation 71. Is there stastical evidence of lower mean PEF in children with chronic bronchities? Run appropriate test at alpha = 0.05
The Cardiac Care Network in Ontario, Canada, wants to determine whether the wait for by- pass surgery is longer than the wait for angiography. A sample of 539 bypass patients waited, on average, 19 days with standard deviation 10 days; a sample of 847 angiography patients waited, on average, 18 days with standard deviation 9 days. What kind of a test should CCN perform? z-interval to estimate the difference in two proportions t-interval to estimate the difference in two means Chi-square test for association t-test for the difference in two means z-test for the difference in two proportions ANOVA
The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.1 days and a standard deviation of 2.3 days. What is the 80th percentile for recovery times?(round answer to two decimal places )
A tire manufacturer claims that the mean life of its tire is 75,000 miles. The mean of a sample of 50 tires is 74,200 miles with a standard deviation of 2300 miles. Using an alpha of 5%, does the manufacturer’s claim appear to hold ture? Explain.
The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches. Men the same age have mean height 69.3 inches with standard deviation 2.8 inches. (a) What is the z-score for a woman 61 inches tall? z-score = (b) What is the z-score for a man 70 inches tall? z-score =
The number of ants per acre in the forest is normally distributed with mean 44,000 and standard deviation 12,292. Let X = number of ants in a randomly selected acre of the forest. Round all answers to 4 decimal places where possible. Find the first quartile. __ ants (round your answer to a whole number)
nd the 30th and 98th percentile values cf a normal variable with Mean of 12_and Variance of 30 Anot This I NEED PARTBI b), Suppose we sample 3 items from this population. Find the variables that correspond to the central 85% Confident Interval range of the sum of these 3 samples.
can someone please help me? I keep getting this wrong so if someone could explain that would help so much. Thanks!! the t statistic test is -3.108 by the way!
A mandatory competency test for high school sophomores has a normal distribution with a meanof 390 and a standard deviation of 112. Round the final answers to the nearest whole number and intermediate z-valuecalculations to 2 decimal places.The top 6% of students receive $500. What is the minimum score you would need to receive this award?The minimum score needed to receive the award is
The time until recharge for a battery in a laptop computer under common conditions is normally distributed with a mean of 260 minutes and a standard deviation of 50 minutes.The battery life in minutes that is exceeded with 95% probability is closest to