Page < 2 > of 3 2) In the figure, the magnetic field in the circular region of radius R changes with time according to B = (2.00 t² – 4.00 t + 0.800) T. Calculate the magnitude and direction of the force exerted on an electron located at point P2 at time t= 2.00 s where r2 = 2R = 5.00 cm. (Ignore P1.) Hint: Note that the force on the electron is caused by the electric field induced at P2. x x x PIX X X x Xx x x x x x x x B. Pin

Page < 2 > of 3 2) In the figure, the magnetic field in the circular region of radius R changes with time according to B = (2.00 t² – 4.00 t + 0.800) T. Calculate the magnitude and direction of the force exerted on an electron located at point P2 at time t= 2.00 s where r2 = 2R = 5.00 cm. (Ignore P1.) Hint: Note that the force on the electron is caused by the electric field induced at P2. x x x PIX X X x Xx x x x x x x x B. Pin

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter11: Magnetic Forces And Fields

Section: Chapter Questions

Problem 65AP: An electron moving with a velocity v=(4.0i+3.0j+2.0k)106m/s enters a region where there is a uniform...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

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Page
2
> of 3
ZOOM
+
2) In the figure, the magnetic field in the circular region of radius R
changes with time according to B = (2.00 t³ – 4.00 t² + 0.800) T.
Calculate the magnitude and direction of the force exerted on an
electron located at point P2 at time t = 2.00 s where r2 = 2R = 5.00 cm.
(Ignore P1.) Hint: Note that the force on the electron is caused by the
electric field induced at P2.
X X
P
r2
x'x X
Bin

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