P01: For the continuous floor system in Fig 1 below, calculate the following: a. be for the beam T-section at section A-A and B-B, b. Design moment for Doubly Reinforced Rectangular beam section (Fig. 4) at section C-C. c. Design moment for Singly reinforced T- beam section (Fig. 2) at section A-A. (See Hint) d. Design moment for Doubly reinforced T-beam section (Fig. 3) at section B-B. (Optional-for further knowledge) Given: a. bw = 1 ft; b. f'c = 4000 psi and fy = 60 ksi. c. Central floor beam spanning in horizontal direction. d. The floor system has a uniform spacing between beams. HINT: For a typical floor system, mid-span sections are subjected to positive bending. Section A-A has large compression zone; hence compression steel may not be required for additional moment strength in this case. Assuming section will include No. 3 or No. 4 stirrups (compression steel in the section is not shown in the figure which is placed for reinforcement continuity requirements), d= 24 in- 3.5 in= 20.5 i and d₁= 24 in – 2.5 in = 21.5 in). 7 Slab thickness = 5 in. 24 ft Figure 1 Continuous Floor System 10 ft 10 ft

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
icon
Related questions
Question
Reinforced Concrete Design Only do Part A, B, and C
P01: For the continuous floor system in Fig 1 below, calculate the following:
a. be for the beam T-section at section A-A and B-B,
b. Design moment for Doubly Reinforced Rectangular beam section (Fig. 4) at section C-C.
c. Design moment for Singly reinforced T-beam section (Fig. 2) at section A-A. (See Hint)
d. Design moment for Doubly reinforced T- beam section (Fig. 3) at section B-B. (Optional - for
further knowledge)
Given:
a. bw = 1 ft;
b. f'c = 4000 psi and fy = 60 ksi.
c. Central floor beam spanning in horizontal direction.
d. The floor system has a uniform spacing between beams.
HINT: For a typical floor system, mid-span sections are subjected to positive bending. Section A-A has a
large compression zone; hence compression steel may not be required for additional moment strength in
this case. Assuming section will include No. 3 or No. 4 stirrups (compression steel in the section is not
shown in the figure which is placed for reinforcement continuity requirements), d= 24 in- 3.5 in= 20.5 in
and d₁= 24 in - 2.5 in = 21.5 in).
A
Slab thickness= 5 in.
24 ft
B
Figure 1 Continuous Floor System
10 ft
10 ft
Transcribed Image Text:P01: For the continuous floor system in Fig 1 below, calculate the following: a. be for the beam T-section at section A-A and B-B, b. Design moment for Doubly Reinforced Rectangular beam section (Fig. 4) at section C-C. c. Design moment for Singly reinforced T-beam section (Fig. 2) at section A-A. (See Hint) d. Design moment for Doubly reinforced T- beam section (Fig. 3) at section B-B. (Optional - for further knowledge) Given: a. bw = 1 ft; b. f'c = 4000 psi and fy = 60 ksi. c. Central floor beam spanning in horizontal direction. d. The floor system has a uniform spacing between beams. HINT: For a typical floor system, mid-span sections are subjected to positive bending. Section A-A has a large compression zone; hence compression steel may not be required for additional moment strength in this case. Assuming section will include No. 3 or No. 4 stirrups (compression steel in the section is not shown in the figure which is placed for reinforcement continuity requirements), d= 24 in- 3.5 in= 20.5 in and d₁= 24 in - 2.5 in = 21.5 in). A Slab thickness= 5 in. 24 ft B Figure 1 Continuous Floor System 10 ft 10 ft
3 No. 5 bars
be 72 in.
.
6 No. 7 bars
12 in.
Figure 2 T-Beam section at A-A section
13 No. 8 bars|
be = 72 in.
2 No. 8 (No. 25)
6 No. 10 (No. 32)
3 No. 7 bars
3.5 in.
12 in.
I=2.5 in.
H
5 in.
12"
-2.5 in.
Figure 3 T-Beam Section at B-B section
- Ismt
5 in.
3 No. 5 bars
24"
24 in.
Figure 4 Rectangular Beam Section at C-C
24 in.
Transcribed Image Text:3 No. 5 bars be 72 in. . 6 No. 7 bars 12 in. Figure 2 T-Beam section at A-A section 13 No. 8 bars| be = 72 in. 2 No. 8 (No. 25) 6 No. 10 (No. 32) 3 No. 7 bars 3.5 in. 12 in. I=2.5 in. H 5 in. 12" -2.5 in. Figure 3 T-Beam Section at B-B section - Ismt 5 in. 3 No. 5 bars 24" 24 in. Figure 4 Rectangular Beam Section at C-C 24 in.
Expert Solution
steps

Step by step

Solved in 8 steps with 30 images

Blurred answer
Knowledge Booster
Roofing elements and materials
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Structural Analysis
Structural Analysis
Civil Engineering
ISBN:
9781337630931
Author:
KASSIMALI, Aslam.
Publisher:
Cengage,
Structural Analysis (10th Edition)
Structural Analysis (10th Edition)
Civil Engineering
ISBN:
9780134610672
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Principles of Foundation Engineering (MindTap Cou…
Principles of Foundation Engineering (MindTap Cou…
Civil Engineering
ISBN:
9781337705028
Author:
Braja M. Das, Nagaratnam Sivakugan
Publisher:
Cengage Learning
Fundamentals of Structural Analysis
Fundamentals of Structural Analysis
Civil Engineering
ISBN:
9780073398006
Author:
Kenneth M. Leet Emeritus, Chia-Ming Uang, Joel Lanning
Publisher:
McGraw-Hill Education
Sustainable Energy
Sustainable Energy
Civil Engineering
ISBN:
9781337551663
Author:
DUNLAP, Richard A.
Publisher:
Cengage,
Traffic and Highway Engineering
Traffic and Highway Engineering
Civil Engineering
ISBN:
9781305156241
Author:
Garber, Nicholas J.
Publisher:
Cengage Learning