Reinforced Concrete Design Only do Part A, B, and C P01: For the continuous floor system in Fig 1 below, calculate the following:a. be for the beam T-section at section A-A and B-B,b. Design moment for Doubly Reinforced Rectangular beam section (Fig. 4) at section C-C.c. Design moment for Singly reinforced T-beam section (Fig. 2) at section A-A. (See Hint)d. Design moment for Doubly reinforced T- beam section (Fig. 3) at section B-B. (Optional - forfurther knowledge)Given:a. bw = 1 ft;b. f'c = 4000 psi and fy = 60 ksi.c. Central floor beam spanning in horizontal direction.d. The floor system has a uniform spacing between beams.HINT: For a typical floor system, mid-span sections are subjected to positive bending. Section A-A has alarge compression zone; hence compression steel may not be required for additional moment strength inthis case. Assuming section will include No. 3 or No. 4 stirrups (compression steel in the section is notshown in the figure which is placed for reinforcement continuity requirements), d= 24 in- 3.5 in= 20.5 inand d₁= 24 in - 2.5 in = 21.5 in).ASlab thickness= 5 in.24 ftBFigure 1 Continuous Floor System10 ft10 ft 3 No. 5 barsbe 72 in..6 No. 7 bars12 in.Figure 2 T-Beam section at A-A section13 No. 8 bars|be = 72 in.2 No. 8 (No. 25)6 No. 10 (No. 32)3 No. 7 bars3.5 in.12 in.I=2.5 in.H5 in.12"-2.5 in.Figure 3 T-Beam Section at B-B section- Ismt5 in.3 No. 5 bars24"24 in.Figure 4 Rectangular Beam Section at C-C24 in.

Compressive strength of concrete, Yield strength of steel, Width of web, Thickness of slab, To…

P01: For the continuous floor system in Fig 1 below, calculate the following: a. be for the beam T-section at section A-A and B-B, b. Design moment for Doubly Reinforced Rectangular beam section (Fig. 4) at section C-C. c. Design moment for Singly reinforced T- beam section (Fig. 2) at section A-A. (See Hint) d. Design moment for Doubly reinforced T-beam section (Fig. 3) at section B-B. (Optional-for further knowledge) Given: a. bw = 1 ft; b. f'c = 4000 psi and fy = 60 ksi. c. Central floor beam spanning in horizontal direction. d. The floor system has a uniform spacing between beams. HINT: For a typical floor system, mid-span sections are subjected to positive bending. Section A-A has large compression zone; hence compression steel may not be required for additional moment strength in this case. Assuming section will include No. 3 or No. 4 stirrups (compression steel in the section is not shown in the figure which is placed for reinforcement continuity requirements), d= 24 in- 3.5 in= 20.5 i and d₁= 24 in – 2.5 in = 21.5 in). 7 Slab thickness = 5 in. 24 ft Figure 1 Continuous Floor System 10 ft 10 ft

P01: For the continuous floor system in Fig 1 below, calculate the following: a. be for the beam T-section at section A-A and B-B, b. Design moment for Doubly Reinforced Rectangular beam section (Fig. 4) at section C-C. c. Design moment for Singly reinforced T- beam section (Fig. 2) at section A-A. (See Hint) d. Design moment for Doubly reinforced T-beam section (Fig. 3) at section B-B. (Optional-for further knowledge) Given: a. bw = 1 ft; b. f'c = 4000 psi and fy = 60 ksi. c. Central floor beam spanning in horizontal direction. d. The floor system has a uniform spacing between beams. HINT: For a typical floor system, mid-span sections are subjected to positive bending. Section A-A has large compression zone; hence compression steel may not be required for additional moment strength in this case. Assuming section will include No. 3 or No. 4 stirrups (compression steel in the section is not shown in the figure which is placed for reinforcement continuity requirements), d= 24 in- 3.5 in= 20.5 i and d₁= 24 in – 2.5 in = 21.5 in). 7 Slab thickness = 5 in. 24 ft Figure 1 Continuous Floor System 10 ft 10 ft

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Reinforced Concrete Design Only do Part A, B, and C

P01: For the continuous floor system in Fig 1 below, calculate the following:
a. be for the beam T-section at section A-A and B-B,
b. Design moment for Doubly Reinforced Rectangular beam section (Fig. 4) at section C-C.
c. Design moment for Singly reinforced T-beam section (Fig. 2) at section A-A. (See Hint)
d. Design moment for Doubly reinforced T- beam section (Fig. 3) at section B-B. (Optional - for
further knowledge)
Given:
a. bw = 1 ft;
b. f'c = 4000 psi and fy = 60 ksi.
c. Central floor beam spanning in horizontal direction.
d. The floor system has a uniform spacing between beams.
HINT: For a typical floor system, mid-span sections are subjected to positive bending. Section A-A has a
large compression zone; hence compression steel may not be required for additional moment strength in
this case. Assuming section will include No. 3 or No. 4 stirrups (compression steel in the section is not
shown in the figure which is placed for reinforcement continuity requirements), d= 24 in- 3.5 in= 20.5 in
and d₁= 24 in - 2.5 in = 21.5 in).
A
Slab thickness= 5 in.
24 ft
B
Figure 1 Continuous Floor System
10 ft
10 ft

3 No. 5 bars
be 72 in.
.
6 No. 7 bars
12 in.
Figure 2 T-Beam section at A-A section
13 No. 8 bars|
be = 72 in.
2 No. 8 (No. 25)
6 No. 10 (No. 32)
3 No. 7 bars
3.5 in.
12 in.
I=2.5 in.
H
5 in.
12"
-2.5 in.
Figure 3 T-Beam Section at B-B section
- Ismt
5 in.
3 No. 5 bars
24"
24 in.
Figure 4 Rectangular Beam Section at C-C
24 in.

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Step 1: Determine the given variables.

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Step 2: (a) Determine the effective width.

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Step 3: (b) Determine the depth of neutral axis.

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Step 4: check the assumption.

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Step 5: Determine the deisgn moment strength.

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Step 6: (c) Determine the depth of neutral axis.

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