P L1 L2 Clevis and pin 1 a= 0,6 m T. Clevis and pin 2 -2.0 m -b = 1.0 m. Center of gravity of plate Steel plate (2.5 x 1.5 x 0,08 m) PROBLEM 1.8-6
P L1 L2 Clevis and pin 1 a= 0,6 m T. Clevis and pin 2 -2.0 m -b = 1.0 m. Center of gravity of plate Steel plate (2.5 x 1.5 x 0,08 m) PROBLEM 1.8-6
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter8: Centroids And Distributed Loads
Section: Chapter Questions
Problem 8.71P
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A steel plate of dimensions 2.5 x 1.5 x 0.08 m and weighing 23.1 kN is hoisted by steel cables with lengths L1 = 3.2 m and L2 = 3.9 m that are each attached to the plate by a clevis and pin (see figure). The pins through the clevises are 18 mm in diameter and are located 2.0 m apart. The orientation angles are measured to be s = 94.4' and a = 54.9° For these conditions, first determine the cable forces T1 and T2, then find the average shear stress Taver in both pin 1 and pin 2, and then the average bearing stress ?? between the steel plate and each pin. Ignore the weight of the cables.
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