P (kN) d (mm) t (mm) www 85 80 25 The beam in Figure Q2(a) has a cross-section as shown in Figure Q2(b), where the values of P, d and t are given in Table Q2. (a) Determine reactions, RA and RB. (b) Determine the shear force at section AB and bending moment at point B. (c) Determine the neutral axis and moment of inertia of the cross section of the beam (d) Determine the maximum tensile and compressive bending stress of the beam at point B. (Formula: Omax = "). Then, plot the bending stress distribution. vQ (e) Determine the maximum shear stress of at section AB. (Formula: 7 =). It P (kN) t (m A В d (mm) d (mm) 0.8 m 1.6 m t(mm) t (mm) (b) (a) Figure Q2

P (kN) d (mm) t (mm) www 85 80 25 The beam in Figure Q2(a) has a cross-section as shown in Figure Q2(b), where the values of P, d and t are given in Table Q2. (a) Determine reactions, RA and RB. (b) Determine the shear force at section AB and bending moment at point B. (c) Determine the neutral axis and moment of inertia of the cross section of the beam (d) Determine the maximum tensile and compressive bending stress of the beam at point B. (Formula: Omax = "). Then, plot the bending stress distribution. vQ (e) Determine the maximum shear stress of at section AB. (Formula: 7 =). It P (kN) t (m A В d (mm) d (mm) 0.8 m 1.6 m t(mm) t (mm) (b) (a) Figure Q2

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

P (kN)
d (mm)
t (mm)
www
85
80
25
The beam in Figure Q2(a) has a cross-section as shown in Figure Q2(b), where the values of P,
d and t are given in Table Q2.
(a) Determine reactions, RA and Rg.
(b) Determine the shear force at section AB and bending moment at point B.
(c) Determine the neutral axis and moment of inertia of the cross section of the beam
(d) Det
hine the maximum tensile and compressive bending stress
the beam at point B.
(Formula: omax =). Then, plot the bending stress distribution.
(e) Determine the maximum shear stress of at section AB. (Formula: T =).
P (kN)
t (m
d (mm)
1.6 m
0.8 m
d (mm)
t (mm)
t(mm)
(a)
Figure Q2

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