The cantilever beam is supported by a fixed support at A, and subjected to the force F-470 lb and thecouple M = 3210 ft-lb. Draw the shear force and bending moment diagrams (in your homeworkdocumentation) and determine the equations for V(x) and M(x). Take z = 0 at point A.2013 Michael SwanbomF₁(CC)abBY NC SAaSupport ReactionsThe force reaction at A isThe couple moment reaction at A isValues for dimensions on the figure are given in the following table. Note the figure may not be to scale.Variable Value4 ft3.2 ftShear Force and Bending Moment EquationsIn section AB:V(x)=In section BC:V(x)=Blb (take up as positive).lb and 'M(x)=Mlb and 'M(x)=b-Cft-lb (take counterclockwise as positive).ft-lb.ft-lb.

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The cantilever beam is supported by a fixed support at A, and subjected to the force F-470 lb and the couple M = 3210 ft-lb. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(x) and M(x). Take z = 0 at point A.

The cantilever beam is supported by a fixed support at A, and subjected to the force F-470 lb and the couple M = 3210 ft-lb. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(x) and M(x). Take z = 0 at point A.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

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The cantilever beam is supported by a fixed support at A, and subjected to the force F-470 lb and the
couple M = 3210 ft-lb. Draw the shear force and bending moment diagrams (in your homework
documentation) and determine the equations for V(x) and M(x). Take z = 0 at point A.
2013 Michael Swanbom
F₁
(CC)
a
b
BY NC SA
a
Support Reactions
The force reaction at A is
The couple moment reaction at A is
Values for dimensions on the figure are given in the following table. Note the figure may not be to scale.
Variable Value
4 ft
3.2 ft
Shear Force and Bending Moment Equations
In section AB:
V(x)=
In section BC:
V(x)=
B
lb (take up as positive).
lb and 'M(x)=
M
lb and 'M(x)=
b-
C
ft-lb (take counterclockwise as positive).
ft-lb.
ft-lb.

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