P-2 A driven closed-ended pile, circular in crosssection, is shown in the Figure. Calculate thefollowing:Layer IGroundwater3 mtáblea. The ultimate point load using Meyerhof'sprocedure.3 mLayer IIb. The ultimate frictional resistance Qs.[Take K = 1.4 and ô'= 0.6º']c. The allowable load of the pile (use FS = 315 mLayer IId. Calculate the (a), (b) and (c) if the layer III was aClay soil with C,=80 kPa (use ca-method by Terzaghiand FS = 3)%3DLayer IY = 15.7 kN/m³4' = 32°Layer II= 18.2 kN/m3 Ysat = 19.2 kN/m³Layer III381 mmYsat4' = 32°c' = 0= 40°c' = 0c' = 0

Answered: Image /qna-images/answer/99c15a78-f920-4ec7-9e41-1680d929b236.jpg

P-2 A driven closed-ended pile, circular in cross section, is shown in the Figure. Calculate the following: Layer I Groundwater table : 3 m a. The ultimate point load using Meyerhof's procedure. 3 m Layer II b. The ultimate frictional resistance Qs. [Take K = 1.4 and ô'= 0.6w'] c. The allowable load of the pile (use FS = 3 d. Calculate the (a), (b) and (c) if the layer III was a Clay soil with C=80 kPa (use a-method by Terzaghi and FS = 3) 15 m Layer III %3D Layer I Y = 15.7 kN/m³ o' = 32° c' = 0 Layer II = 18.2 kN/m3 Ysat = 19.2 kN/m³ Layer III 381 mm Ysat 6' = 32° c' = 0 o' = 40° c' = 0

P-2 A driven closed-ended pile, circular in cross section, is shown in the Figure. Calculate the following: Layer I Groundwater table : 3 m a. The ultimate point load using Meyerhof's procedure. 3 m Layer II b. The ultimate frictional resistance Qs. [Take K = 1.4 and ô'= 0.6w'] c. The allowable load of the pile (use FS = 3 d. Calculate the (a), (b) and (c) if the layer III was a Clay soil with C=80 kPa (use a-method by Terzaghi and FS = 3) 15 m Layer III %3D Layer I Y = 15.7 kN/m³ o' = 32° c' = 0 Layer II = 18.2 kN/m3 Ysat = 19.2 kN/m³ Layer III 381 mm Ysat 6' = 32° c' = 0 o' = 40° c' = 0

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.

Question

P-2 A driven closed-ended pile, circular in cross
section, is shown in the Figure. Calculate the
following:
Layer I
Groundwater
3 m
táble
a. The ultimate point load using Meyerhof's
procedure.
3 m
Layer II
b. The ultimate frictional resistance Qs.
[Take K = 1.4 and ô'= 0.6º']
c. The allowable load of the pile (use FS = 3
15 m
Layer II
d. Calculate the (a), (b) and (c) if the layer III was a
Clay soil with C,=80 kPa (use ca-method by Terzaghi
and FS = 3)
%3D
Layer I
Y = 15.7 kN/m³
4' = 32°
Layer II
= 18.2 kN/m3 Ysat = 19.2 kN/m³
Layer III
381 mm
Ysat
4' = 32°
c' = 0
= 40°
c' = 0
c' = 0

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