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A driven closed-ended pile, circular in cross section, 3 m Y = 15.7 kN/m³ 6'=32″ Groundwater is shown in Fig. 3. Calculate the following: a) The ultimate point load using Meyerhof's procedure. 3 m b) The ultimate frictional resistance Qs. Take K=1.4 and 8' = 0.6 '. 15 m c) The allowable load to be resisted by this pile, using factor of safety = 4. 381 mm Fig. 3 c=0 table Yat = 18.2 kN/m 6' = 32° c' = 0 Yat 19.2 kN/m³ 6' = 40° c=0

A driven closed-ended pile, circular in cross section, 3 m Y = 15.7 kN/m³ 6'=32″ Groundwater is shown in Fig. 3. Calculate the following: a) The ultimate point load using Meyerhof's procedure. 3 m b) The ultimate frictional resistance Qs. Take K=1.4 and 8' = 0.6 '. 15 m c) The allowable load to be resisted by this pile, using factor of safety = 4. 381 mm Fig. 3 c=0 table Yat = 18.2 kN/m 6' = 32° c' = 0 Yat 19.2 kN/m³ 6' = 40° c=0

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A driven closed-ended pile, circular in cross section, 3 m Y = 15.7 kN/m³ 6'=32″ Groundwater is shown in Fig. 3. Calculate the following: a) The ultimate point load using Meyerhof's procedure. 3 m b) The ultimate frictional resistance Qs. Take K=1.4 and 8' = 0.6 '. 15 m c) The allowable load to be resisted by this pile, using factor of safety = 4. 381 mm Fig. 3 c=0 table Yat = 18.2 kN/m 6' = 32° c' = 0 Yat 19.2 kN/m³ 6' = 40° c=0
Transcribed Image Text:A driven closed-ended pile, circular in cross section, 3 m Y = 15.7 kN/m³ 6'=32″ Groundwater is shown in Fig. 3. Calculate the following: a) The ultimate point load using Meyerhof's procedure. 3 m b) The ultimate frictional resistance Qs. Take K=1.4 and 8' = 0.6 '. 15 m c) The allowable load to be resisted by this pile, using factor of safety = 4. 381 mm Fig. 3 c=0 table Yat = 18.2 kN/m 6' = 32° c' = 0 Yat 19.2 kN/m³ 6' = 40° c=0
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